python - The Foundry NUKE 中的色差
问题描述
所以我试图用 Python 代码直接制作一个绘画节点组,这样我就可以将它用于未来的项目,但我似乎无法从这个色差公式中获得 nuke 公式的强大部分(我也是Nuke 的新手,所以如果有更好的写作方式,请告诉我这将是非常棒的,谢谢,或者如果我完全做错了也让我知道)
以下色差公式用于创建差异图像:|(r1,g1,b1) – (r2,g2,b2)| = ((r1 – r2)^2 + (g1 –g2)^2 + (b1 – b2)^2)^1/2。
nRedShuffle = nuke.nodes.Shuffle()
nRedShuffle['red'].setValue('red')
nRedShuffle['green'].setValue('red')
nRedShuffle['blue'].setValue('red')
nRedShuffle['alpha'].setValue('red')
nGreenShuffle = nuke.nodes.Shuffle()
nGreenShuffle['red'].setValue('green')
nGreenShuffle['green'].setValue('green')
nGreenShuffle['blue'].setValue('green')
nGreenShuffle['alpha'].setValue('green')
#...(so on for the rest of rgba1 and rgba2)
nGreenShuffle2 = nuke.nodes.Shuffle()
nGreenShuffle2['red'].setValue('green')
nGreenShuffle2['green'].setValue('green')
nGreenShuffle2['blue'].setValue('green')
nGreenShuffle2['alpha'].setValue('green')
nBlueShuffle2 = nuke.nodes.Shuffle()
nBlueShuffle2['red'].setValue('blue')
nBlueShuffle2['green'].setValue('blue')
nBlueShuffle2['blue'].setValue('blue')
nBlueShuffle2['alpha'].setValue('blue')
#I am having troubles with the powers below
redDiff = nuke.nodes.Merge2(operation='minus', inputs=[nRedShuffle2, nRedShuffle])
redDiffMuli = nuke.nodes.Merge2(operation='multiply', inputs=[redDiff, redDiff])
greenDiff = nuke.nodes.Merge2(operation='minus', inputs=[nGreenShuffle2, nGreenShuffle])
greenDiffMuli = nuke.nodes.Merge2(operation='multiply', inputs=[greenDiff, greenDiff])
blueDiff = nuke.nodes.Merge2(operation='minus', inputs=[nBlueShuffle2, nBlueShuffle])
blueDiffMuli = nuke.nodes.Merge2(operation='multiply', inputs=[blueDiff, blueDiff])
redGreenAdd = nuke.nodes.Merge2(operation='plus', inputs=[redDiffMuli, greenDiffMuli])
redGreenBlueAdd = nuke.nodes.Merge2(operation='plus', inputs=[redGreenAdd, blueDiffMuli])
解决方案
这里至少有两种方法来实现Color Difference
两个图像的公式。您可以在 Merge 节点中使用difference
op,也可以在字段中为节点内的每个通道编写公式MergeExpression
:
每个通道的表达式就像这样简单:
abs(Ar-Br)
abs(Ag-Bg)
abs(Ab-Bb)
Python 命令
您可以使用.nodes.MergeExpression
方法:
import nuke
merge = nuke.nodes.MergeExpression(expr0='abs(Ar-Br)',
expr1='abs(Ag-Bg)',
expr2='abs(Ab-Bb)')
或常规.createNode
语法:
merge = nuke.createNode('MergeExpression')
merge['expr0'].setValue('abs(Ar-Br)')
merge['expr1'].setValue('abs(Ag-Bg)')
merge['expr2'].setValue('abs(Ab-Bb)')
完整代码版
import nuke
import nukescripts
red = nuke.createNode("Constant")
red['color'].setValue([1,0,0,1])
merge = nuke.createNode('MergeExpression')
merge['expr0'].setValue('abs(Ar-Br)')
merge['expr1'].setValue('abs(Ag-Bg)')
merge['expr2'].setValue('abs(Ab-Bb)')
yellow = nuke.createNode("Constant")
yellow['color'].setValue([1,1,0,1])
merge.connectInput(0, yellow)
nuke.toNode('MergeExpression1').setSelected(True)
nukescripts.connect_selected_to_viewer(0)
# Auto-alignment in Node Graph
for everyNode in nuke.allNodes():
everyNode.autoplace()
考虑!MergeExpression
node 比常规Merge(difference)
node慢得多。
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