python - Python十六进制字符串到整数转换错误

Question

我正在尝试将此库从 Javascript 移植到 Python，但在尝试将十六进制字符串转换为整数时不断收到一个奇怪的错误。它适用于短字符串，但由于某种原因会阻塞较大的字符串：

ValueError: invalid literal for int() with base 16: '14fdbc5ade9e3d4097f421fe7b4b54ad05883d589c3b3f6648b5e0ea2b64b359158087b793b859a4c51af0fd8c1edb7a92b8d5843c1a2d659929357c7e1869784435d6dcfd8d29b619194333b38655493eb4eb3deeffbf339e91c7c0f6113b4bb6672f49'

代码如下所示：

def stretch(value):
    hexadecimal = hex(value)[2:]
    buffer = hexadecimal
    while True:
        buffer += record_separator + hexadecimal
        if len(buffer) >= minimum_digits:
            break
    return int(buffer, 16)

标签： pythontype-conversionintegerhex

Answer 1

Python 3 对其整数值没有限制。

因此，您可以使用 int(hex_string, 16) 将大字符串转换为整数值。

s = '14fdbc5ade9e3d4097f421fe7b4b54ad05883d589c3b3f6648b5e0ea2b64b359158087b793b859a4c51af0fd8c1edb7a92b8d5843c1a2d659929357c7e1869784435d6dcfd8d29b619194333b38655493eb4eb3deeffbf339e91c7c0f6113b4bb6672f49'

s_int = int(s, 16)

print(s_int)

结果

546755182137531943293891170863886409257177002102958031106970218913938945216495276608761007929774380907079475078176395384371438944791022503587328767282546555465705414556027853888426781796298321719051075009856267471199860627126795651319803721