首页 > 解决方案 > Terraform 模块:使用模块创建多个资源并相互引用

问题描述

我定义了一个变量tenants,它是一个映射:

variable tenants {
  type        = map
  default     = {
    tenant1 = {
      name      = "Tenant1"
    },
    tenant2 = {
      name    = "Tenant2"
    }
  }
}

在根文件中,我调用一个模块tenant如下:

module "tenant" {
  source = "./modules/tenant"

  for_each     =    var.tenants
  tenant = each.value.name
}

子模块tenant如下所示:

resource "mso_tenant" "tenant" {
  name            = var.tenant
}

我在子模块中定义了一个输出:

output "mso_tenant" {
  value = mso_tenant.tenant

在根目录下的输出文件中,我执行以下操作来打印所有租户:

output "tenant_names" {
    value       = { for p in sort(keys(var.tenants)) : p => module.tenant[p].mso_tenant.name }
}

到目前为止一切顺利,以上所有工作。

现在我有另一个名为 的变量schemas,也是一个地图。一个租户可以有多个模式。所以我定义了以下

variable schemas {
  type        = map
  default     = {
    schema1 = {
      name          = "Schema1",
      template_name = "Template1",
      tenant = <refer to tenant1>      <==== refer to tenant module
    },
    schema2 = {
      name          = "Schema2"
      template_name = "Template2",
      tenant = <refer to tenant2>      <==== refer to tenant module
    },
    schema3 = {
      name          = "Schema3"
      template_name = "Template3",
      tenant = <refer to tenant1>      <==== refer to tenant module
    },
  }
}

在根目录下的 main.tf 文件中,我想要执行以下操作:

module "schema" {
  source = "./modules/schema"

  for_each     =    var.schemas
  name            = each.value.name
  template_name   = each.value.template_name
  tenant_id       = each.value.tenant
}

如何在架构变量中或直接在架构模块中引用各自的租户?

更新:

尝试解决方案1:

在变量文件中,我按如下方式传递了租户:

    schema1 = {
      name          = "Schema1",
      template_name = "Template1",
      tenant        = module.tenant["tenant1"].mso_tenant
    }

错误:不允许使用变量

尝试解决方案2:

module "tenant" {
  source = "./modules/tenant"

  for_each     =    var.tenants
  tenant       =    each.value.name
}

module "schema" {
  source = "./modules/schema"

  for_each     =    var.schemas
  name            = each.value.name
  template_name   = each.value.template_name
  tenant_id       = module.tenant[each.value.tenant].mso_tenant
}

导致以下错误:

  on main.tf line 30, in module "schema":
  30:   tenant_id       = module.tenant[each.value.tenant].mso_tenant
    |----------------
    | each.value is object with 2 attributes

This object does not have an attribute named "tenant".

标签: terraformterraform0.12+

解决方案


如果要引用租户资源,tenant1可以使用module.tenant["tenant1"].mso_tenant并将其直接分配给模式或第二个模块的输入变量。

当您使用模块for_each module.tenant时,是由tenant_id 键入的对象映射。每个对象都包含租户子模块的所有输出。

重构

根变量定义:

variable tenants {
  type = map
  default = {
    tenant1 = {
      name = "Tenant1"
    },
    tenant2 = {
      name = "Tenant2"
    }
  }
}

variable schemas {
  type = map
  default = {
    schema1 = {
      name          = "Schema1",
      template_name = "Template1",
      tenant_id     = "tenant1"
    },
    schema2 = {
      name          = "Schema2"
      template_name = "Template2",
      tenant_id     = "tenant2"
    },
    schema3 = {
      name          = "Schema3"
      template_name = "Template3",
      tenant_id     = "tenant1"
    },
  }
}

在根目录中调用这样的模块:

module "tenant" {
  source = "./modules/tenant"

  for_each = var.tenants

  tenant = each.value.name
}

module "schema" {
  source = "./modules/schema"

  for_each = var.schemas

  name          = each.value.name
  template_name = each.value.template_name
  tenant        = module.tenant[each.value.tenant_id].mso_tenant
}

根输出定义可能如下所示:

output "tenant_names" {
  value = { for p in sort(keys(var.tenants)) : p => module.tenant[p].mso_tenant.name }
}

output "schemas" {
  value = module.schema
}

这导致以下输出:

Apply complete! Resources: 0 added, 0 changed, 0 destroyed.

Outputs:

schemas = {
  "schema1" = {
    "schema" = {
      "name" = "Schema1"
      "template_name" = "Template1"
      "tenant" = {
        "name" = "Tenant1"
      }
    }
  }
  "schema2" = {
    "schema" = {
      "name" = "Schema2"
      "template_name" = "Template2"
      "tenant" = {
        "name" = "Tenant2"
      }
    }
  }
  "schema3" = {
    "schema" = {
      "name" = "Schema3"
      "template_name" = "Template3"
      "tenant" = {
        "name" = "Tenant1"
      }
    }
  }
}
tenant_names = {
  "tenant1" = "Tenant1"
  "tenant2" = "Tenant2"
}

用于模拟的模式模块:

variable "name" {
  type = string
}

variable "template_name" {
  type = string
}

variable "tenant" {
  type = any
}

output "schema" {
  value = {
    name          = var.name
    template_name = var.template_name
    tenant        = var.tenant
  }
}

租户模块用于模拟:

variable "tenant" {
  type = string
}

locals {
  mso_tenant = {
    tenant = {
      name = var.tenant
    }
  }
}

output "mso_tenant" {
  value = local.mso_tenant.tenant
}

希望在完整的上下文中这更容易,更清楚;)


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