首页 > 解决方案 > link_to 和 destroy 方法

问题描述

我有一个应用程序,您可以在其中将游戏(通过 API 找到)添加到用户的库中,但我也希望用户从库中删除游戏。但是,我不确定我是否使用了正确的 link_to 路径,或者问题是否出在我的控制器上。

路线

Rails.application.routes.draw do
  get 'library_game/index'
  devise_for :users
  root to: 'pages#home'
  get '/games', to: 'games#index', as: :index
  get '/user/:id', to: 'user#show'
  resource :user, only: [] do
  resources :games, only: [:create, :destroy]
end
  get '/user/:id/library', to: 'library#index', as: :library
  post '/user/:id/library', to: 'games#create', as: :create
  delete 'user/:id/library', to: 'games#destroy', as: :destroy
end

我的游戏模型

class Game < ApplicationRecord
  has_many :library_games
  has_many :libraries, through: :library_games
  has_many :users, through: :libraries
  serialize :data
  attr_accessor :game_id

  def fetch_data
    game = GiantBomb::Game.detail(game_id)
    self.data = Hash[game.instance_variables.map { |var| [var.to_s[1..-1], game.instance_variable_get(var)] } ]
  end

  def to_giant_bomb_game
    GiantBomb::Game.new(data)
  end
end

我要删除的链接地址:

<%= link_to 'Remove from library', destroy_path(current_user, game_id: game.id), method: :delete %>

我的销毁控制器方法:

def destroy
    current_user.games.where(game_id: params[:id]).destroy_all
    redirect_to library_path
  end

就我现在所拥有的,我收到了这个错误:ActiveRecord::StatementInvalid in GamesController#destroy PG::UndefinedColumn: ERROR: column games.game_id does not exist

所以这个错误引发了控制器的问题,但我想知道真正的罪魁祸首是否是我的 link_to 没有传递正确的数据。我应该将什么传递给我的 link_to?

标签: ruby-on-railsdestroylink-to

解决方案


如果连接是LibraryGame(因为它有 alibrary_id和 a game_id)那么这个

resource :user, only: [] do
  resources :games, only: [:create, :destroy]
end

需要是

resources :users, only: [] do
  resources :library_games, only: [:create, :destroy], shallow: true
end

,shallow: true为您提供诸如users/1/library_games/xindex、create 和 new 之类的路由,但为您提供诸如library_games/xshow、edit、update 和 destroy 之类的路由。两全其美。

然后你的链接将是<%= link_to "Remove from Library", library_game_path(library_game), method: :delete %>.


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