java - 使用 mockito 和 Junit5 使用参数模拟静态 void 方法

Question

我正在尝试模拟一个带有参数的静态 void 方法SMTPTools.send(Message)

我的部门：

    <dependency>
      <groupId>org.junit.jupiter</groupId>
      <artifactId>junit-jupiter-engine</artifactId>
      <version>5.7.0</version>
      <scope>test</scope>
    </dependency>
    <dependency>
      <groupId>org.mockito</groupId>
      <artifactId>mockito-core</artifactId>
      <version>3.6.0</version>
      <scope>test</scope>
    </dependency>
    <dependency>
      <groupId>org.mockito</groupId>
      <artifactId>mockito-inline</artifactId>
      <version>3.6.0</version>
      <scope>test</scope>
    </dependency>
    <dependency>
      <groupId>org.mockito</groupId>
      <artifactId>mockito-junit-jupiter</artifactId>
      <version>3.6.0</version>
      <scope>test</scope>
    </dependency>

尝试：

    try (MockedStatic<SMTPTools> smtpToolsMocked = Mockito.mockStatic(SMTPTools.class)) {
      smtpToolsMocked.when((msg) -> SMTPTools.send(msg)).thenAnswer((Answer<Void>) invocation -> null);
    }

但它甚至没有编译原因

MockedStatic 类型中的 when(MockedStatic.Verification) 方法不适用于参数 (( msg) -> {})

但我明白为什么

标签： javastaticmockingmockitojunit5

Answer 1

好的，它适用于：

  @Test
  public void staticTest() throws Exception {
    try (MockedStatic<SMTPTools> smtpToolsMocked = Mockito.mockStatic(SMTPTools.class)) {
      Message msg = null;
      smtpToolsMocked.when((msg) -> SMTPTools.send(msg)).thenAnswer((Answer<Void>) invocation -> null);
      SMTPTools.send(msg);
      smtpToolsMocked.verify(Mockito.times(1), () -> SMTPTools.send(msg));
    }
  }