c - CS50 pset3 多个程序没有 print_winner 功能(没有打印两个选举的获胜者)
问题描述
我刚刚完成了我的多个 cs50 程序的编程。它运行顺利,但是当我运行检查时,它说它不打印获胜者的名字,但确实如此。这是代码,有人可以帮助我吗?正如我所说,该功能print_winner()
有效,如果我运行,debug50
我可以看到。使用命令行参数,我假设宣布不超过 9 个候选人,选择我想要多少票,投票给候选人,然后程序假设宣布获胜者。问题是它可以做到,但根据 bot50 它没有。
#include <cs50.h>
#include <stdio.h>
#include <string.h>
// Max number of candidates
#define MAX 9
// Candidates have name and vote count
typedef struct
{
string name;
int votes;
}
candidate;
// Array of candidates
candidate candidates[MAX];
// Number of candidates
int candidate_count;
// Function prototypes
bool vote(string name);
void print_winner(void);
int main(int argc, string argv[])
{
// Check for invalid usage
if (argc < 2)
{
printf("Usage: plurality [candidate ...]\n");
return 1;
}
// Populate array of candidates
candidate_count = argc - 1;
if (candidate_count > MAX)
{
printf("Maximum number of candidates is %i\n", MAX);
return 2;
}
for (int i = 0; i < candidate_count; i++)
{
candidates[i].name = argv[i + 1];
candidates[i].votes = 0;
}
int voter_count = get_int("Number of voters: ");
// Loop over all voters
for (int i = 0; i < voter_count; i++)
{
string name = get_string("Vote: ");
// Check for invalid vote
if (!vote(name))
{
printf("Invalid vote.\n");
}
}
// Display winner of election
print_winner();
}
// Update vote totals given a new vote
bool vote(string name)
{
for (int i = 0; i < candidate_count; i++)
{
if (strcmp(candidates[i].name, name) == 0)
{
candidates[i].votes++;
return true;
}
}
return false;
}
// Print the winner (or winners) of the election
void print_winner(void)
{
int n = candidate_count;
typedef struct
{
string name;
int votes;
}
bubble;
bubble bubbles[n];
for (int i = 0; i < n; i++)
{
for (int j = i + 1; j < n; j++)
{ //doing a bubble sort to move the max vote at the end and doing
the same with the candidate name
if (candidates[i].votes > candidates[j].votes)
{
bubbles[0].votes = candidates[i].votes;
candidates[i].votes = candidates[j].votes;
candidates[j].votes = bubbles[0].votes;
bubbles[0].name = candidates[i].name;
candidates[i].name = candidates[j].name;
candidates[j].name = bubbles[0].name;
}
}
}
for (int i = 1; i <= n; i++)
{
if (candidates[n - i].votes == candidates[n - 1].votes)
{
printf("%s ", candidates[n - i].name);
}
printf("\n");
}
}
解决方案
很高兴看到更多代码,例如定义/初始化的位置candidates
和candidate_count
位置,例如,如果您正在执行#include <string>
这表明您实际上using
std::string
是字符串的其他版本,而不是其他版本的字符串。
如果是这种情况,那么您的使用std::string
就很奇怪。通常strcmp()
需要一个指向 C 风格的字符数组或类型的指针const char*
......就像printf()
......所以你应该附加.c_str()
到你的使用name
and candidates[n - i].name
。
即strcmp(candidates[i].name.c_str(), name.c_str())
和printf("%s ", candidates[n - i].name.c_str());
不过,这又是假设您实际使用的是std::string
.
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