java - 在相应的 ASCII 日历位置返回多维数组项
问题描述
我目前正在尝试在我创建的日历应用程序上添加查看事件的功能。启动时，当用户在菜单中键入“ev”时，他们可以添加带有月、日和标题的事件，然后将所有这些添加到 [12][monthlength] 的多维数组上的相应位置]。一旦他们将事件添加到数组中，当显示某个月份时，事件所在的框应该显示事件的标题，最后一点是我卡住的地方。
这是通过用户输入（ev 按钮）添加数据的数组：
public static Object[][] EVENTS = new Object[13][31];
代表 12 个月，每个月 31 天。
打印出数组看起来像这样：
[[null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null], [null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null], [null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null], [null, EVENT, TITLE, null, NOTHER, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null], [null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null], [null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null], [null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null], [null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null], [null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null], [null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null], [null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null], [null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null], [null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null]]
虽然这看起来很乱，但如果您查看第三个子数组，您可以看到通过用户输入添加的示例数据。
最后尝试将这些数据显示到日历上是事情变得复杂的地方。这是我的代码：
public static void drawRow(int week, int days, boolean firstWeek, int startDay, int month) {
header(SIZE * 7);
// this is for the firstt row of each row. includes day
// draws each box for week length
// if current loop count < start day, do an empty box
//
if (firstWeek == true) {
// deals with height, days passed = length
for (int i = 1; i <= SIZE / 2; i++) {
if (startDay != 1) {
System.out.print("|");
}
spaceRow(startDay - 1, true, startDay, month, week);
if (i == 1) {
numRow(week, days - startDay + 1, true);
System.out.print("|");
} else {
spaceRow(days - startDay, true, startDay, month, week);
for (int last = 1; last <= SIZE - 1; last++) {
System.out.print(" ");
}
System.out.print("|");
}
System.out.println();
}
} else {
numRow(week, days, false);
System.out.println("|");
// this is for the rest (without numbers)
// height of each box
for (int height = 1; height <= SIZE / 2 - 1; height++) {
spaceRow(days, false, startDay, month, week);
}
}
}
public static void numRow(int week, int days, boolean first) {
for (int col = 1; col <= days; col++) {
if (first == true && col == 1) {
System.out.print("");
} else {
System.out.print("|");
}
// get length of current days number
String weekStr = String.valueOf(week);
int length = weekStr.length();
if (week <= 31) {
System.out.print(week++);
} else {
System.out.print(" ");
}
for (int space = 1; space <= SIZE - length - 1; space++) {
System.out.print(" ");
}
}
}
public static void spaceRow(int days, boolean first, int startDay, int mnth, int week) {
//
// makes each row (full length)
for (int col2 = 1; col2 <= days; col2++) {
// use week -1 to get correct day
week++;
if (first == true && col2 == 1) {
} else {
System.out.print("|");
}
//
if (EVENTS[mnth][week - 1] != null) {
System.out.print("x");
} else {
for (int space = 1; space <= SIZE - 1; space++) {
System.out.print(" ");
}
}
}
if (startDay == 7) {
System.out.print("|");
} else {
System.out.print("|");
}
// if its the last row being drawn (when first ==true), dont go to the next row
if (first == false) {
System.out.println();
}
}
// division between weeks (=====)
public static void header(int sz) {
for (int top = 1; top <= sz; top++) {
System.out.print("=");
}
System.out.println();
}
还有比这更多的代码，但我认为这足以了解正在发生的事情。如果你向下看大约 3/4，你可以看到“if (EVENTS[mnth][week - 1]”这是我试图保持逻辑来决定是否应该将事件放置在空白空间或不是。（“x”）只是为了测试目的，但现在我得到一个索引超出范围的错误。
下面是更多上下文的日历：
__//
/.__.\
\ \/ /
`_/ \
\- )
\____/
| | /
======================================================================
\ \ \
11
SUN MON TUE WED THU FRI SAT
======================================================================
| | | | | |1 |2 |
| | | | | | | |
| | | | | | | |
| | | | | | | |
| | | | | | | |
======================================================================
|3 |4 |5 |6 |7 |8 |9 |
| | | | | | | |
| | | | | | | |
| | | | | | | |
| | | | | | | |
======================================================================
|10 |11 |12 |13 |14 |15 |16 |
| | | | | | | |
| | | | | | | |
| | | | | | | |
| | | | | | | |
======================================================================
|17 |18 |19 |20 |21 |22 |23 |
| | | | | | | |
| | | | | | | |
| | | | | | | |
| | | | | | | |
======================================================================
|24 |25 |26 |27 |28 |29 |30 |
| | | | | | | |
| | | | | | | |
| | | | | | | |
| | | | | | | |
======================================================================
Month: 11
Day: 2
Please type a command
'e' to enter a date and display the correspoding calendar
't' to get todays date and display todays calendar
'n' to display the next month
'p' to display the previous month
'd' to exit the program
'ev' to add an event
我知道这是一个混乱的问题，但任何输入或提示都是值得赞赏的。如果您需要更多信息，请尽快回复。谢谢！
解决方案
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