c - toupper 函数不适用于指针取消引用？

Question

我正在编写一个程序来确定输入是白面包还是甜面包，并将确定面包类型的值作为指针传递给函数：

#include <ctype.h>

void WhiteSweetChoosing(char *orWhiteSweet);

int main(){

    char orWhiteSweet ,isDouble, isManual;
    WhiteSweetChoosing(&orWhiteSweet);
    printf("%c", orWhiteSweet);

    return 0;
}

void WhiteSweetChoosing(char *orWhiteSweet){
    printf("Please enter your bread type\n");
    printf("W for white and S for sweet:");
    scanf(" %c", orWhiteSweet);
    *orWhiteSweet = toupper(*orWhiteSweet);

    while(*orWhiteSweet != 'S' && *orWhiteSweet != 'W'){
        printf("Please enter valid character\n");
        printf("W for white and S for sweet:");
        scanf(" %c", orWhiteSweet);
    }

}

但是，这不起作用，因为 toupper 函数似乎没有将新值分配给取消引用的指针。我在函数下放了一个 printf 来验证 toupper 不起作用。

但是当我将值分配给一个新变量而不是旧的取消引用指针本身时，它开始工作：

void WhiteSweetChoosing(char *orWhiteSweet){
    printf("Please enter your bread type\n");
    printf("W for white and S for sweet:");
    scanf(" %c", orWhiteSweet);
    char WorS = toupper(*orWhiteSweet);

    while(WorS != 'S' && WorS != 'W'){
        printf("Please enter valid character\n");
        printf("W for white and S for sweet:");
        scanf(" %c", orWhiteSweet);
        WorS = toupper(*orWhiteSweet);
    }

}

如果有人能解释原因，我将不胜感激，谢谢

标签： c

Answer 1

您忘记申请toupper秒或更晚读取的值scanf()。

void WhiteSweetChoosing(char *orWhiteSweet){
    printf("Please enter your bread type\n");
    printf("W for white and S for sweet:");
    scanf(" %c", orWhiteSweet);
    *orWhiteSweet = toupper(*orWhiteSweet);

    while(*orWhiteSweet != 'S' && *orWhiteSweet != 'W'){
        printf("Please enter valid character\n");
        printf("W for white and S for sweet:");
        scanf(" %c", orWhiteSweet);
        *orWhiteSweet = toupper(*orWhiteSweet); /* add this */
    }

}