首页 > 解决方案 > 复制 Tkinter 树视图

问题描述

我正在尝试在另一个窗口中显示 ttk 树视图。似乎唯一的选择是遍历原始树视图并相应地填充新树视图。

但是我似乎无法将所有(许多)子文件夹放在正确的位置,从 2d 级别开始,一切都混在一起了(即,我得到了根文件夹及其子文件夹,然后似乎插入了子文件夹在随机位置)。

功能是:

    def getsubchildren(item=''):
        children = []
        for child in original_treeview.get_children(item):
            i = new_treeview.insert(item, 'end', text=original_treeview.item(child) 
                                   ['text'],values=original_treeview.item(child)['values'])
            children.append(i)

        for subchild in children: 
            getsubchildren(subchild)

并使用 , 调用函数以getsubchildren(item='')从第一级开始迭代。一定是我做错了什么,但我无法确定问题所在,而且我修改函数的尝试只会产生更差的结果。任何想法 ?

谢谢,

标签: python-3.xtkintertreeview

解决方案


在不知道项目深度的情况下,您需要检查项目是否有子项。如果是这样,您需要该函数在循环中调用自身。这是一个工作示例:

import tkinter as tk
from tkinter import ttk

root = tk.Tk()

maintree = ttk.Treeview(root)
maintree.pack()

first = maintree.insert("","end",text='first')
second= maintree.insert(first,"end",text='second')
third= maintree.insert(second,"end",text='third')
fourth= maintree.insert(third,"end",text='fourth')

st = maintree.insert("","end",text='1st')
nd= maintree.insert(st,"end",text='2nd')
rd= maintree.insert(nd,"end",text='3rd')
th= maintree.insert(rd,"end",text='4th')

top = tk.Toplevel(root)
subtree = ttk.Treeview(top)
subtree.pack()

def copy_item_tree(item,child):
    for child in maintree.get_children(child):
        item = subtree.insert(item,"end",
                              text=maintree.item(child)['text'])
        if maintree.get_children(child):
            copy_item_tree(item,child)
def copy_tree():
    for child in maintree.get_children():
        item = subtree.insert("","end",text=maintree.item(child)['text'])
        copy_item_tree(item,child)

button = tk.Button(root,text='Copy Tree', command=copy_tree)
button.pack(fill='x')
root.mainloop()

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