python - 共享numpy数组时的python多处理

Question

我想通过利用多处理来部分更改大型 numpy 数组中的值。

也就是说，我想最后得到[[100, 100, 100], [100, 100, 100]]。

但是下面的代码是错误的，它说“RuntimeError：SynchronizedArray 对象只能通过继承在进程之间共享”

我应该怎么办？谢谢。

import numpy as np
import multiprocessing

from multiprocessing import RawArray, Array


def change_array(array, i, j):
    X_np = np.frombuffer(array.get_obj(), dtype=np.float64).reshape(2, 3)
    X_np[i, j] = 100
    print(np.frombuffer(array.get_obj()))

if __name__ == '__main__':
    X_shape = (2, 3)
    data = np.array([[1.1, 2.2, 3.3], [4.4, 5.5, 6.6]])
    X = Array('d', X_shape[0] * X_shape[1])
    # Wrap X as an numpy array so we can easily manipulates its data.
    X_np = np.frombuffer(X.get_obj()).reshape(X_shape)
    # Copy data to our shared array.
    np.copyto(X_np, data)

    pool = multiprocessing.Pool(processes=3)

    result = []
    for i in range(2):
        for j in range(3):
            result.append(pool.apply_async(change_array, (X, i, j,)))

    result = [r.get() for r in result]
    pool.close()
    pool.join()

    print(np.frombuffer(X.get_obj()).reshape(2, 3))

标签： pythonarraysnumpypython-multiprocessing

Answer 1

You need to make two changes:

1. Use a multiprocessing.Array instance with locking (actually, the default) rather than a "plain" Array.
2. Do not pass the array instance as an argument to your worker function. Instead you should initialize each processor in your pool with the array as a global value.

import numpy as np
import multiprocessing

from multiprocessing import RawArray, Array


def initpool(arr):
    global array
    array = arr

def change_array(i, j):
    X_np = np.frombuffer(array.get_obj(), dtype=np.float64).reshape(2, 3)
    X_np[i, j] = 100
    print(np.frombuffer(array.get_obj()))

if __name__ == '__main__':
    X_shape = (2, 3)
    data = np.array([[1.1, 2.2, 3.3], [4.4, 5.5, 6.6]])
    X = multiprocessing.Array('d', X_shape[0] * X_shape[1], lock=True)
    # Wrap X as an numpy array so we can easily manipulates its data.
    X_np = np.frombuffer(X.get_obj()).reshape(X_shape)
    # Copy data to our shared array.
    np.copyto(X_np, data)

    pool = multiprocessing.Pool(processes=3, initializer=initpool, initargs=(X,))

    result = []
    for i in range(2):
        for j in range(3):
            result.append(pool.apply_async(change_array, (i, j,)))

    result = [r.get() for r in result]
    pool.close()
    pool.join()

    print(np.frombuffer(X.get_obj()).reshape(2, 3))

Prints:

[100.    2.2   3.3   4.4   5.5   6.6]
[100.  100.    3.3   4.4   5.5   6.6]
[100.  100.  100.    4.4   5.5   6.6]
[100.  100.  100.  100.    5.5   6.6]
[100.  100.  100.  100.  100.    6.6]
[100. 100. 100. 100. 100. 100.]
[[100. 100. 100.]
 [100. 100. 100.]]

Update

Since in this case the values being changed in the data array do not depend on the existing values in that array, there is no need for function change_array to have access to the array and it can instead, as suggested by Frank Yellin, just return a tuple of the indices to be changed with the new value. But I did want to show you how you would pass the array for those situations where the function did need to access/modify the array. The following code, in this instance, however, is all that you need (I have made a few simplifications):

import numpy as np
import multiprocessing


def change_array(i, j):
    return i, j, 100

if __name__ == '__main__':
    data = np.array([[1.1, 2.2, 3.3], [4.4, 5.5, 6.6]])
    with multiprocessing.Pool(processes=3) as pool:
        result = [pool.apply_async(change_array, (i, j)) for i in range(2) for j in range(3)]
        for r in result:
            i, j, value = r.get()
            data[i, j] = value
        print(data)

Or:

import numpy as np
import multiprocessing
import itertools


def change_array(t):
    i, j = t
    return i, j, 100

if __name__ == '__main__':
    data = np.array([[1.1, 2.2, 3.3], [4.4, 5.5, 6.6]])
    with multiprocessing.Pool(processes=3) as pool:
        for i, j, value in pool.map(change_array, itertools.product(range(2), range(3))):
            data[i, j] = value
        print(data)