python - 如何避免将“全局”与 asyncio（电视节目）一起使用？

Question

据我所知，在 python 中使用“全局”是一种不好的做法，但我不知道如何在这里避免它。先感谢您。

import asyncio
from telethon import TelegramClient, sync, events

api_id = ***
api_hash = '***'

client = TelegramClient('session_name', api_id, api_hash).start()

channel_id = ***

@client.on(events.NewMessage(chats=channel_id))
async def handler(event):
    text = event.raw_text.lower()

    global task

    if text == 'start':
        task = client.loop.create_task(main())
        await client.send_message(channel_id, 'task was started')

    if text == 'stop':
        task.cancel()
        await client.send_message(channel_id, 'task was canceled')

async def main():
    while True:
        await client.send_message(channel_id, 'do something')
        await asyncio.sleep(3)

client.run_until_disconnected()

标签： pythonpython-asynciotelethon

Answer 1

查看文档，我找不到将客户端与类一起使用的推荐方法，但您应该始终能够自己连接它。例如：

class MyClient:
    def __init__(self, client):
        self.task = None
        self.client = client

    async def on_message(self, channel_id, event):
        text = event.raw_text.lower()

        if text == 'start':
            self.task = self.client.loop.create_task(self.main(channel_id))
            await self.client.send_message(channel_id, 'task was started')

        if text == 'stop':
            self.task.cancel()
            await self.client.send_message(channel_id, 'task was canceled')

    async def main(self, channel_id):
        while True:
            await self.client.send_message(channel_id, 'do something')
            await asyncio.sleep(3)

def run_client():
    # instantiate telegram client, my client, and connect the two
    api_id = ***
    api_hash = '***'

    channel_id = ***

    client = TelegramClient('session_name', api_id, api_hash).start()
    my_client = MyClient(client)

    @client.on(events.NewMessage(chats=channel_id))
    async def handle(event):
        await my_client.on_message(channel_id, event)

    client.run_until_disconnected()

run_client()