首页 > 解决方案 > 如何使用矩在数组中获得最近的下一次?

问题描述

我想找到最接近给定时间的下一次,我从堆栈溢出中得到了这段代码,但我无法得到想要的结果

// Current time in millis
const now = +moment('10:07', 'HH:mm').format('x');
// List of times
const times = ["10:00", "10:18", "23:30", "12:00"];
// Times in milliseconds
const timesInMillis = times.map(t => +moment(t, "HH:mm").format("x"));

function closestTime(arr, time) {
  return arr.reduce(function(prev, curr) {
    return Math.abs(curr - time) < Math.abs(prev - time) ? curr : prev;
  });
}

const closest = moment(closestTime(timesInMillis, now)).format('HH:mm');

// closest is 10:00 but i want the next time 10:18
console.log(closest);
<script src="https://cdnjs.cloudflare.com/ajax/libs/moment.js/2.29.1/moment.min.js"></script>

标签: javascriptmomentjs

解决方案


完全不需要片刻

24小时时间可排序,可直接比较

const times = ["10:00", "10:18", "23:30", "12:00"].sort();

const getClosest = targetTime => times.find(time => time >= targetTime) || "N/A";

console.log(getClosest("10:07"));

console.log(getClosest("11:30"));

console.log(getClosest("13:30"));

console.log(getClosest("23:40")); // not available in array


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