java - Spring 3.0 中的 Spring 数据
问题描述
如题。我正在使用版本 3.0.7 的 spring:
<dependencies>
<dependency>
<groupId>org.springframework</groupId>
<artifactId>spring-web</artifactId>
<version>3.0.7.RELEASE</version>
</dependency>
<dependency>
<groupId>org.springframework</groupId>
<artifactId>spring-webmvc</artifactId>
<version>3.0.7.RELEASE</version>
</dependency>
<!-- https://mvnrepository.com/artifact/org.springframework.security/spring-security-core -->
<dependency>
<groupId>org.springframework.security</groupId>
<artifactId>spring-security-core</artifactId>
<version>3.0.7.RELEASE</version>
</dependency>
<dependency>
<groupId>org.springframework.security</groupId>
<artifactId>spring-security-config</artifactId>
<version>3.0.7.RELEASE</version>
</dependency>
<!-- Spring Security Web -->
<dependency>
<groupId>org.springframework.security</groupId>
<artifactId>spring-security-web</artifactId>
<version>3.0.7.RELEASE</version>
</dependency>
<!-- https://mvnrepository.com/artifact/org.flywaydb/flyway-core -->
<dependency>
<groupId>org.flywaydb</groupId>
<artifactId>flyway-core</artifactId>
<version>3.2.1</version>
</dependency>
<dependency>
<groupId>org.testcontainers</groupId>
<artifactId>testcontainers</artifactId>
<version>1.14.3</version>
<scope>test</scope>
</dependency>
<dependency>
<groupId>org.testcontainers</groupId>
<artifactId>postgresql</artifactId>
<version>1.14.3</version>
<scope>test</scope>
</dependency>
<dependency>
<groupId>org.projectlombok</groupId>
<artifactId>lombok</artifactId>
<version>1.18.12</version>
<scope>provided</scope>
</dependency>
<dependency>
<groupId>org.postgresql</groupId>
<artifactId>postgresql</artifactId>
<version>42.2.17</version>
</dependency>
<dependency>
<groupId>org.springframework.data</groupId>
<artifactId>spring-data-jpa</artifactId>
<version>1.4.5.RELEASE</version>
</dependency>
</dependencies>
我正在尝试在@Entity、@Table 注释等中创建模型类:
package main.model.user;
import lombok.*;
import org.springframework.data.annotation.Id;
import org.springframework.security.core.GrantedAuthority;
import org.springframework.security.core.userdetails.UserDetails;
import java.util.Collection;
import java.util.HashSet;
import java.util.Set;
import java.util.UUID;
@Entity
@Getter
@Builder(toBuilder = true)
@EqualsAndHashCode
@AllArgsConstructor
@NoArgsConstructor
@Table(name = "user_entity")
public class User implements UserDetails {
@Id
@GeneratedValue(generator = "UUID")
@GenericGenerator(
name = "UUID",
strategy = "org.hibernate.id.UUIDGenerator"
)
@Column(name = "id", updatable = false, nullable = false)
private UUID id;
@Column(name = "first_name")
private String firstName;
@Column(name = "last_name")
private String lastName;
@Column(name = "username")
private String username;
@Column(name = "password")
private String password;
@Column(name = "email")
private String email;
@Column(name = "phone_number")
private String phoneNumber;
@Enumerated(EnumType.STRING)
@Column(name = "body_part_type")
private BodyPartType favouriteBodyPartType;
@ElementCollection(targetClass = String.class, fetch = FetchType.EAGER)
@CollectionTable(name = "permission", joinColumns = @JoinColumn(name = "user_id", referencedColumnName = "id"))
@Column(name = "permission_name", nullable = false)
private Set<String> roles = new HashSet<>();
@Override
public Collection<GrantedAuthority> getAuthorities() {
return roles.stream()
.map(SimpleGrantedAuthority::new)
.collect(Collectors.toSet());
}
@Override
public boolean isAccountNonExpired() {
return true;
}
@Override
public boolean isAccountNonLocked() {
return true;
}
@Override
public boolean isCredentialsNonExpired() {
return true;
}
@Override
public boolean isEnabled() {
return true;
}
}
但Entity, Table, GeneratedValue, GenericGenerator
被标记为红色,我无法导入它们。我有个问题。我对 spring-data 有错误的依赖关系还是它是如何工作的?Mabe它在spring 3.0中不存在?
创建相同Repositories
(从 spring-boot 应用程序复制的代码):
package main.user;
import main.exercise.BodyPartType;
import main.model.user.User;
import org.springframework.data.jpa.repository.Query;
import org.springframework.data.repository.CrudRepository;
import org.springframework.data.repository.query.Param;
import org.springframework.stereotype.Repository;
import java.util.List;
import java.util.Optional;
import java.util.UUID;
@Repository
public interface UserRepository extends CrudRepository<User, UUID> {
@Query("SELECT CASE WHEN COUNT(user) > 0 THEN true ELSE false END FROM User user WHERE user.id =:userID")
boolean doesAccountExistsWithID(@Param("userID") UUID accountID);
Optional<User> findByUsername(String name);
Optional<User> findByEmail(String email);
Optional<User> findByPhoneNumber(String phoneNumber);
List<User> findUsersByFavouriteBodyPartType(BodyPartType bodyPartType);
}
是否有可能在 Spring 3.0 中制作这样的东西?
解决方案
使用这些依赖项,您可以使用@Entity 和@Repository。
import java.util.UUID;
import javax.persistence.Column;
import javax.persistence.Entity;
import javax.persistence.GeneratedValue;
import javax.persistence.Id;
import javax.persistence.Table;
import org.hibernate.annotations.GenericGenerator;
@Table(name = "user_entity")
@Entity
public class EntityExample {
@Id
@GeneratedValue(generator = "UUID")
@GenericGenerator(
name = "UUID",
strategy = "org.hibernate.id.UUIDGenerator"
)
@Column(name = "id", updatable = false, nullable = false)
private UUID id;
}
<project xmlns="http://maven.apache.org/POM/4.0.0"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 http://maven.apache.org/xsd/maven-4.0.0.xsd">
<modelVersion>4.0.0</modelVersion>
<parent>
<groupId>org.springframework</groupId>
<artifactId>spring-parent</artifactId>
<version>3.1.4.RELEASE</version>
<relativePath /> <!-- lookup parent from repository -->
</parent>
<groupId>com.main.mytest</groupId>
<artifactId>email-registration</artifactId>
<version>0.0.1-SNAPSHOT</version>
<build>
<plugins>
<plugin>
<groupId>org.apache.maven.plugins</groupId>
<artifactId>maven-compiler-plugin</artifactId>
<configuration>
<source>1.8</source>
<target>1.8</target>
</configuration>
</plugin>
</plugins>
</build>
<dependencies>
<dependency>
<groupId>org.springframework.data</groupId>
<artifactId>spring-data-jpa</artifactId>
<version>2.4.2</version>
</dependency>
<dependency>
<groupId>org.springframework.data</groupId>
<artifactId>spring-data-commons</artifactId>
<version>2.4.2</version>
</dependency>
</dependencies>
</project>
如果您不想在 pom 中将 spring 作为父级,那么您可以添加以下依赖项:
<project xmlns="http://maven.apache.org/POM/4.0.0"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 http://maven.apache.org/xsd/maven-4.0.0.xsd">
<modelVersion>4.0.0</modelVersion>
<groupId>com.main.mytest</groupId>
<artifactId>email-registration</artifactId>
<version>0.0.1-SNAPSHOT</version>
<build>
<plugins>
<plugin>
<groupId>org.apache.maven.plugins</groupId>
<artifactId>maven-compiler-plugin</artifactId>
<configuration>
<source>1.8</source>
<target>1.8</target>
</configuration>
</plugin>
</plugins>
</build>
<dependencies>
<dependency>
<groupId>org.springframework</groupId>
<artifactId>spring-context</artifactId>
<version>5.3.2</version>
</dependency>
<dependency>
<groupId>org.hibernate</groupId>
<artifactId>hibernate-annotations</artifactId>
<version>3.5.6-Final</version>
</dependency>
<dependency>
<groupId>javax.persistence</groupId>
<artifactId>javax.persistence-api</artifactId>
<version>2.2</version>
</dependency>
</dependencies>
</project>
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