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python - 在 python 中练习循环时遇到问题

问题描述

import time
import random
import math

start = 1
stop = 10

for i in range(start, stop):
    time.sleep(1)
    print("\ni = {}".format(i), end = "")
    count = 3 + random.randint(1,5)
    print(", count = {}".format(count))
    nums = []
    while len(nums) < count:
        for j in range(count):
            time.sleep(0.3)
            try:
                num = random.randint(-10,100)
                log = round(math.log(num),1)
            except:
                time.sleep(2)
                print("\nagain")
                break
            nums.append(log)
            print("\rnums = {}".format(nums), end = "")

我想要做的是count为每次迭代提供一个随机整数i，然后使用while循环将日志附加num到，直到等于nums的长度。这里是一个-10到100之间的随机整数，如果给定为0或以下，我想从最开始重新开始循环，也就是，这样我就可以指定new和make new 。numscountnumnumfor i in range(start, stop):time.sleep(1)countnums

所以我执行了上面的代码，它又从while len(nums) < count:.

例如，我所期望的是

i = 1, count = 7
nums = [4.2, 4.4, 2.9, 4.4]
again
i = 1, count = 5
nums = [3.5, 3.6, 4.2]
again
i = 1, count = 6
nums = [2.0, 3.2, 3.5, 3.6, 4.2, 4.5]
i = 2, count = 5
nums = [4.5, 4.1, 4.0, 3.9, 3.8]
i = 3, count = 6
nums = [4.3, 3.8]
again
i = 3, count = 5
nums = [3.0, 3.4, 4.6, 3.6, 3.1]

等等

我得到的是

i = 1, count = 7
nums = [4.2, 4.4, 2.9, 4.4, 3.2, 2.6]
again
nums = [4.2, 4.4, 2.9, 4.4, 3.2, 2.6, 4.0, 1.4, 3.5, 3.6, 3.5, 4.4, 2.9]
i = 2, count = 4

again
nums = [4.5, 4.1, 4.0, 3.9]
i = 3, count = 6
nums = [4.3, 3.8]
again
nums = [4.3, 3.8, 3.6, 2.3, 3.4, 4.6, 3.6, 3.1]
i = 4, count = 5
nums = [1.4, 3.0, 4.0, 4.4, 4.0]
i = 5, count = 7
nums = [4.4, 2.9, 3.5, 4.2, 3.6, 4.4, 4.6]

等等

标签： pythonfor-loopwhile-loopbreak

解决方案

num把它全部放在一个函数中，每当小于或等于0时再次调用它

import time
import random
import math

start = 1
stop = 10

def whatever():
    for i in range(start, stop):
        time.sleep(1)
        print("\ni = {}".format(i), end = "")
        count = 3 + random.randint(1,5)
        print(", count = {}".format(count))
        nums = []
        while len(nums) < count:
            for j in range(count):
                time.sleep(0.3)
                num = random.randint(-10,100)

                if num <= 0:
                    time.sleep(2)
                    print("\nagain")
                    whatever()
                else:
                    log = round(math.log(num),1)
                    nums.append(log)

                print("\rnums = {}".format(nums), end = "")

whatever()

num如果小于或等于 0 ，这是循环将再次开始的地方

if num <= 0:
    time.sleep(2)
    print("\nagain")
    whatever()

输出：

i = 1, count = 8
nums = [4.2, 2.9, 3.8, 2.1, 4.0, 4.1, 3.8, 4.4]
i = 2, count = 5
nums = [3.4, 3.2, 3.6, 4.5]
again

i = 1, count = 8
nums = [3.5, 4.2, 4.3, 3.9, 3.5, 4.3, 1.1, 3.2]
i = 2, count = 7

again

i = 1, count = 8
nums = [2.4, 3.0, 4.5, 4.1, 4.2, 4.5, 3.6]

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