arrays - JSONArray 无法转换为 JSONObject 错误,当用作类似代码时
问题描述
当我对注册方法执行相同操作时出现此错误,我在登录时使用它并且效果很好,但是在注册时我收到数组无法转换为 JSONObject 的错误,我正在尝试将数组放入将其转换为 JSONObject 以将其发送到我的数据库 PHP 代码
这是我的注册方法
private void registerUser() {
final String phone = phonenumber.getText().toString().trim();
final String lname = lastname.getText().toString().trim();
final String fname = fullname.getText().toString().trim();
final String mname = middlename.getText().toString().trim();
final String add = address.getText().toString().trim();
final String count = country.getText().toString().trim();
//first we will do the validations
if (TextUtils.isEmpty(lname)) {
lastname.setError("Please your Last Name");
lastname.requestFocus();
return;
}
if (TextUtils.isEmpty(fname)) {
fullname.setError("Please enter your First Name");
fullname.requestFocus();
return;
}
if (TextUtils.isEmpty(add)) {
address.setError("Please enter your Address");
fullname.requestFocus();
return;
}
StringRequest stringRequest = new StringRequest(Request.Method.POST, URLs.URL_REGISTER,
new Response.Listener<String>() {
@Override
public void onResponse(String Response) {
try {
//converting response to json object
JSONObject obj = new JSONObject(Response);
//if no error in response
if (!obj.getBoolean("error")) {
Toast.makeText(getApplicationContext(), obj.getString("message"), Toast.LENGTH_SHORT).show();
//getting the user from the response
JSONObject userJson = obj.getJSONObject("user");
//creating a new user object
User user = new User(
userJson.getString("phone_number"),
userJson.getString("lastname"),
userJson.getString("fullname"),
userJson.getString("middleinitial"),
userJson.getString("country"),
userJson.getString("address")
);
//storing the user in shared preferences
SharedPrefManager.getInstance(getApplicationContext()).userLogin(user);
//starting the profile activity
finish();
startActivity(new Intent(getApplicationContext(), MainActivity.class));
} else {
Toast.makeText(getApplicationContext(), obj.getString("message"), Toast.LENGTH_SHORT).show();
}
} catch (JSONException e) {
e.printStackTrace();
}
}
},
new Response.ErrorListener() {
@Override
public void onErrorResponse(VolleyError error) {
Toast.makeText(getApplicationContext(), error.getMessage(), Toast.LENGTH_SHORT).show();
}
}) {
@Override
protected Map<String, String> getParams() throws AuthFailureError {
Map<String, String> params = new HashMap<>();
params.put("phone_number", phone);
params.put("lastname", lname);
params.put("fullname", fname);
params.put("middleinitial", mname);
params.put("country", count);
params.put("address",add);
return params;
}
};
VolleySingleton.getInstance(this).addToRequestQueue(stringRequest);
}
此代码出现 JSON Array 无法转换的错误,而我的具有相同格式的登录代码正在工作
这是我的登录代码:
private void userLogin(){
//first getting the values
final String phonenumber = etNumber.getText().toString();
//validating inputs
if (TextUtils.isEmpty(phonenumber)) {
etNumber.setError("Please enter your Number");
etNumber.requestFocus();
return;
}
//if everything is fine
StringRequest stringRequest = new StringRequest(Request.Method.POST, URLs.URL_LOGIN,
new Response.Listener<String>() {
@Override
public void onResponse(String response) {
try {
//converting response to json object
JSONObject obj = new JSONObject(response);
//if no error in response
if (!obj.getBoolean("error")) {
Toast.makeText(getApplicationContext(), obj.getString("message"), Toast.LENGTH_SHORT).show();
//getting the user from the response
JSONObject userJson = obj.getJSONObject("user");
//creating a new user object
User user = new User(
userJson.getString("phone_number"),
userJson.getString("lastname"),
userJson.getString("fullname"),
userJson.getString("middleinitial"),
userJson.getString("country"),
userJson.getString("address")
);
//storing the user in shared preferences
SharedPrefManager.getInstance(getApplicationContext()).userLogin(user);
//starting the profile activity
finish();
startActivity(new Intent(getApplicationContext(), MainActivity.class));
} else {
Toast.makeText(getApplicationContext(), obj.getString("message"), Toast.LENGTH_SHORT).show();
}
} catch (JSONException e) {
e.printStackTrace();
}
}
},
new Response.ErrorListener() {
@Override
public void onErrorResponse(VolleyError error) {
Toast.makeText(getApplicationContext(), error.getMessage(), Toast.LENGTH_SHORT).show();
}
})
{
@Override
protected Map<String, String> getParams() throws AuthFailureError {
Map<String, String> params = new HashMap<>();
params.put("phone_number", phonenumber);
return params;
}
};
VolleySingleton.getInstance(this).addToRequestQueue(stringRequest);
}
我在日志上遇到的错误是:
W/System.err: org.json.JSONException: Value [] of type org.json.JSONArray cannot be converted to JSONObject
at org.json.JSON.typeMismatch(JSON.java:112)
at org.json.JSONObject.<init>(JSONObject.java:168)
at org.json.JSONObject.<init>(JSONObject.java:181)
at com.example.redwallet.Register$4.onResponse(Register.java:127)
W/System.err: at com.example.redwallet.Register$4.onResponse(Register.java:120)
at com.android.volley.toolbox.StringRequest.deliverResponse(StringRequest.java:82)
at com.android.volley.toolbox.StringRequest.deliverResponse(StringRequest.java:29)
at com.android.volley.ExecutorDelivery$ResponseDeliveryRunnable.run(ExecutorDelivery.java:102)
at android.os.Handler.handleCallback(Handler.java:883)
at android.os.Handler.dispatchMessage(Handler.java:100)
at android.os.Looper.loop(Looper.java:224)
at android.app.ActivityThread.main(ActivityThread.java:7562)
at java.lang.reflect.Method.invoke(Native Method)
at com.android.internal.os.RuntimeInit$MethodAndArgsCaller.run(RuntimeInit.java:539)
at com.android.internal.os.ZygoteInit.main(ZygoteInit.java:950)
解决方案
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