python - 如何在python中将列表元素分配为二维数组的索引
问题描述
我有一个名为的列表dof[]
,其中包含全局自由度
E1
是一个2D
8x8 顺序
的数组E
是一个2D
18x18 顺序的数组。我想使用dof[]
列表中定义的索引号在 E 中组装 E1。我怎样才能做到这一点?
dof = [0, 1, 2, 3, 6, 7, 8, 9, 2, 3, 4, 5, 8, 9, 10, 11, 6, 7, 8, 9, 12, 13, 14, 15, 8, 9, 10, 11, 14, 15, 16, 17]
E1 = [[0 0 0 0 1 0 0 0]
[1 1 1 1 2 1 1 1]
[2 2 2 2 2 2 2 2]
[3 3 3 3 3 3 3 3]
[4 4 4 4 8 4 4 4]
[5 5 5 5 5 5 5 5]
[6 6 6 6 6 6 6 6]
[7 7 7 7 7 7 7 7]]
和
E = [[0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0.]
[0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0.]
[0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0.]
[0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0.]
[0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0.]
[0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0.]
[0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0.]
[0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0.]
[0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0.]
[0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0.]
[0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0.]
[0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0.]
[0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0.]
[0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0.]
[0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0.]
[0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0.]
[0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0.]
[0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0.]]
E1 应该根据dof[]
列表中定义的索引进行组装。这不是顺序组装。请任何人都可以帮我解决这个问题。
解决方案
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