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php - 循环两个数组，没有来自第一个数组的重复值

问题描述

我不是 100% 确定标题（缺少某些东西），但我 100% 确定我需要什么输出。

$A = array('0' => '1451', '1' => '1451', '2' => '1452', '3' => '1452', '4' => '1453', '5' => '1453', '6' => '1457', '7' => '1460');
$B = array('0' => '22',   '1' => '23',   '2' => '22',   '3' => '23',   '4' => '22',   '5' => '23',   '6' => '',     '7' => '');
    
          for ($i=0, $n=sizeof($A); $i<$n; $i++) {
               echo $A[$i] . ' = ' . $B[$i] . '<br />';
          }
          echo '<hr></hr>';
          echo 'I need this output, is possible: 
          1451 = 22, 23<br />
          1452 = 22, 23<br />
          1453 = 22, 23<br />
          1457 =<br />
          1460 = ';

您可以在此处运行代码：https ://extendsclass.com/php-bin/3baf302

标签： phparrays

解决方案

使用for循环，您需要更改代码：

<?php
// Input
$A = array('0' => '1451', '1' => '1451', '2' => '1452', '3' => '1452', '4' => '1453', '5' => '1453', '6' => '1457', '7' => '1460');
$B = array('0' => '22',   '1' => '23',   '2' => '22',   '3' => '23',   '4' => '22',   '5' => '23',   '6' => '',     '7' => '');

// Output array
$O = array();    
for ($i = 0, $n = count($A); $i < $n; $i++) {
    $O[$A[$i]][] = $B[$i];
}

// Print the output
foreach ($O as $key => $items) {
    echo $key." = ".implode(',', $items)."<br>";
}   
?>

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