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c++ - nvJPEG：编码打包的 BGR

问题描述

好吧，我的目标很简单——尝试使用打包/交错的 BGR 数据（也可以是 RGB）从缓冲区创建 JPEG 编码图像。

NVidia 文档包含一个示例，此处基本上描述了正确的图像输入。

所以我尝试了以下方法：

#include <nvjpeg.h>

// very simple
typedef struct {
    int width;
    int height;
    unsigned char *buffer; 
    unsigned long data_size; 
} my_bitmap_type;


std::vector<unsigned char> BitmapToJpegCUDA(const my_bitmap_type *image) 
{
  nvjpegHandle_t nv_handle;
  nvjpegEncoderState_t nv_enc_state;
  nvjpegEncoderParams_t nv_enc_params;
  cudaStream_t stream = NULL;

  nvjpegStatus_t er;
  nvjpegCreateSimple(&nv_handle);
  nvjpegEncoderStateCreate(nv_handle, &nv_enc_state, stream);
  nvjpegEncoderParamsCreate(nv_handle, &nv_enc_params, stream);

  nvjpegImage_t nv_image;
  nv_image.channel[0] = image->buffer;
  nv_image.pitch[0] = 3 * image->width;

  // Nope, that's for planar images!

  // nv_image.channel[0] = image->buffer;
  // nv_image.channel[1] = image->buffer + image->width * image->height;
  // nv_image.channel[2] = image->buffer + 2 * image->width * image->height;
  // nv_image.pitch[0] = image->width;
  // nv_image.pitch[1] = image->width;
  // nv_image.pitch[2] = image->width;

  er = nvjpegEncodeImage(nv_handle, nv_enc_state, nv_enc_params, &nv_image,
                        NVJPEG_INPUT_BGRI, image->width, image->height, stream);
  LOG(ERROR) << "enc " << er;

  size_t length = 0;
  nvjpegEncodeRetrieveBitstream(nv_handle, nv_enc_state, NULL, &length, stream);

  cudaStreamSynchronize(stream);
  std::vector<unsigned char> jpeg(length);
  nvjpegEncodeRetrieveBitstream(nv_handle, nv_enc_state, jpeg.data(), &length, 0);

  nvjpegEncoderParamsDestroy(nv_enc_params);
  nvjpegEncoderStateDestroy(nv_enc_state);
  nvjpegDestroy(nv_handle);

  return jpeg;
}

记录器说nvjpegEncodeImage只是返回NVJPEG_STATUS_INVALID_PARAMETER，这意味着没有任何作用。如果您怀疑my_bitmap_type填写错误，这里是类似的 turbojpeg 驱动的编码：

#include <turbojpeg.h>

std::vector<unsigned char> BitmapToJpegBuffer(const my_bitmap_type *image)
{
    std::vector<unsigned char> out_data(3 * image->width * image->height);

    cudaError_t err = cudaMemcpy(out_data.data(), image->buffer, image->data_size, cudaMemcpyDeviceToHost);
    if (cudaSuccess != err) {
        LOG(ERROR) << "failed to copy CUDA memory: " << err;
    }

    tjhandle jpeg = tjInitCompress();
    unsigned char *encoded_buf = nullptr;
    long unsigned int encoded_sz = 0;

    int tjres = tjCompress2(jpeg,
                            out_data.data(),
                            image->width,
                            image->width * 3,
                            image->height,
                            TJPF_BGR,
                            &encoded_buf,
                            &encoded_sz,
                            TJSAMP_444,
                            95,
                            TJFLAG_FASTDCT);

    if (tjres != 0) {
        LOG(ERROR) << "jpeg compession failed!";
        return {};
    }

    std::vector<unsigned char> result(encoded_buf, encoded_buf + encoded_sz);
    tjFree(encoded_buf);
    tjDestroy(jpeg);

    return result;
}

... aaand 它工作得很好。

我迫切地想弄清楚代码中缺少什么。将不胜感激任何帮助或建议。

UPD： 使用 CentOS 7 / libnvjpeg-11-1.x86_64 (CUDA 11.1) / gcc 4.8.5

标签： c++cudajpeg

解决方案

好吧，这有点奇怪，但经过一段时间的反复试验后，发现 NVidia 文档缺少基本细节：

    nvjpegCreateSimple(&nv_handle);
    nvjpegEncoderStateCreate(nv_handle, &nv_enc_state, stream);
    nvjpegEncoderParamsCreate(nv_handle, &nv_enc_params, stream);

    // This has to be done, default params are not sufficient
    nvjpegEncoderParamsSetSamplingFactors(nv_enc_params, NVJPEG_CSS_444, stream);

尽管文档明确指出 JPEG 压缩的默认子采样为 4:4:4，但编码不适用于默认编码器参数，必须明确设置子采样。

因此，一行代码解决了所有问题。

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