oracle - 在 oracle 中修剪字符串

Question

我有以下字符串并且只希望输出中的状态名称，请建议我。

'State - Rajasthan,Zone - Jaipur-I,Circle - Circle-P, Jaipur,Ward - Circle-P, jaipur - Ward-2'

所需输出 - 拉贾斯坦邦

标签： oracle

Answer 1

根据该示例，您可以考虑以下几个选项：

SQL> with test (col) as
  2    (select 'State - Rajasthan,Zone - Jaipur-I,Circle - Circle-P, Jaipur,Ward - Circle-P, jaipur - Ward-2'
  3     from dual
  4    )
  5  select substr(col, instr(col, ' ', 1, 2) + 1,
  6                     instr(col, ',') - instr(col, ' ', 1, 2) - 1
  7               ) state,
  8         --
  9         replace(substr(col, 1, instr(col, ',') - 1), 'State - ', '') state2,
 10         --
 11         regexp_substr(col, '\w+', 1, 2) state3
 12  from test;

STATE     STATE2    STATE3
--------- --------- ---------
Rajasthan Rajasthan Rajasthan

SQL>