首页 > 解决方案 > 使用 bs4 python 抓取网页:如何显示足球比赛

问题描述

我是 Python 的初学者,正在尝试创建一个程序,该程序将从 skysports.com 抓取足球/足球赛程,并通过 Twilio 通过 SMS 将其发送到我的手机。我已经排除了 SMS 代码,因为我已经弄清楚了,所以这是到目前为止我遇到的网络抓取代码:

import requests
from bs4 import BeautifulSoup

URL = "https://www.skysports.com/football-fixtures"
page = requests.get(URL)

results = BeautifulSoup(page.content, "html.parser")

d = defaultdict(list)

comp = results.find('h5', {"class": "fixres__header3"})
team1 = results.find('span', {"class": "matches__item-col matches__participant matches__participant--side1"})
date = results.find('span', {"class": "matches__date"})
team2 = results.find('span', {"class": "matches__item-col matches__participant matches__participant--side2"})

for ind in range(len(d)):
    d['comp'].append(comp[ind].text)
    d['team1'].append(team1[ind].text)
    d['date'].append(date[ind].text)
    d['team2'].append(team2[ind].text) 

标签: pythonwebbeautifulsoupscreen-scraping

解决方案


下面应该为您解决问题:

   from bs4 import BeautifulSoup
   import requests
    
    a = requests.get('https://www.skysports.com/football-fixtures')
    soup = BeautifulSoup(a.text,features="html.parser")
    
    teams = []
    for date in soup.find_all(class_="fixres__header2"): # searching in that date
        for i in soup.find_all(class_="swap-text--bp30")[1:]: #skips the first one because that's a heading
            teams.append(i.text)
    
    date = soup.find(class_="fixres__header2").text
    print(date)
    teams = [i.strip('\n') for i in teams]
    for x in range(0,len(teams),2):
        print (teams[x]+" vs "+ teams[x+1])

让我进一步解释一下我所做的:所有的足球都有这个类名-swap-text--bp30 在此处输入图像描述

所以我们可以使用find_all来提取所有具有该名称的类。

一旦我们得到结果,我们可以将它们放入数组“teams = []”,然后将它们附加到 for 循环“team.append(i.text)”中。".text" 去除 html

然后我们可以去掉数组中的“\n”,把它去掉,然后两两打印出数组中的每个字符串。这应该是您的最终输出:

在此处输入图像描述

编辑:为了获得联赛的头衔,我们将做几乎相同的事情:

league = []
for date in soup.find_all(class_="fixres__header2"): # searching in that date
    for i in soup.find_all(class_="fixres__header3"): #skips the first one because that's a heading
        league.append(i.text)

剥离数组并创建另一个:

league = [i.strip('\n') for i in league]
final = []

然后添加最后一段代码,它基本上只是一遍又一遍地打印联盟然后两支球队:

for x in range(0,len(teams),5):
    final.append(teams[x]+" vs "+ teams[x+1])

for i in league:
    print(i)
    for i in final:
        print(i)

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