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javascript - 使用 javascript 切换类

问题描述

我有 3 个按钮。他们都使用 css 选项切换不同的内容display: none; display: flex; 使用 javascript 我在类之间切换.show对于每个按钮我都有一个切换脚本。

它会检测另一个按钮是否已打开但无法正常工作。如果我单击按钮 1，然后单击 2，它将起作用。但是，如果我在那之后点击 3，它会删除所有内容，而不是切换正确的类。

此外，我发现这是一个很长的代码，很可能用更少的东西完成。

我对更少的代码感到满意，但问题的重点是让我明白我做错了什么。

// Button 1
let b1 = document.querySelector(".button1");
let b1_toggle = document.querySelector(".toggle-button-1");
b1.addEventListener("click", function(){
    let b2_toggle = document.querySelector(".toggle-button-2");
    let b3_toggle = document.querySelector(".toggle-button-3");
    let alreadyOpen = false;
    if (b2_toggle.classList.contains("show"), b3_toggle.classList.contains("show")) alreadyOpen = true;
    b2_toggle.classList.remove("show");
    b3_toggle.classList.remove("show");
    if (!alreadyOpen)b1_toggle.classList.toggle("show");
});
// Button 2
let b2 = document.querySelector(".button2");
let b2_toggle = document.querySelector(".toggle-button-2");
b2.addEventListener("click", function(){
    let b1_toggle = document.querySelector(".toggle-button-1");
    let b3_toggle = document.querySelector(".toggle-button-3");
    let alreadyOpen = false;
    if (b1_toggle.classList.contains("show"), b3_toggle.classList.contains("show")) alreadyOpen = true;
    b1_toggle.classList.remove("show");
    b3_toggle.classList.remove("show");
    if (!alreadyOpen)b2_toggle.classList.toggle("show");
});
// Button 3
let b3 = document.querySelector(".button3");
let b3_toggle = document.querySelector(".toggle-button-3");
b3.addEventListener("click", function(){
    let b1_toggle = document.querySelector(".toggle-button-1");
    let b2_toggle = document.querySelector(".toggle-button-2");
    let alreadyOpen = false;
    if (b1_toggle.classList.contains("show"), b2_toggle.classList.contains("show")) alreadyOpen = true;
    b1_toggle.classList.remove("show");
    b2_toggle.classList.remove("show");
    if (!alreadyOpen)b3_toggle.classList.toggle("show");
});
.flex {
  display: flex;
}
.button {
  background-color: red;
  color: white;
  padding: 10px 20px;
}
.toggle-button-1 { display: none;}
.toggle-button-1.show { display: flex;}
.toggle-button-2 { display: none;}
.toggle-button-2.show { display: flex;}
.toggle-button-3 { display: none;}
.toggle-button-3.show { display: flex;}
<div class="flex">
  <div class="button button1">Button1</div>
  <div class="button button2">Button2</div>
  <div class="button button3">button3</div>
</div>

<div class="toggle-button-1">Button 1 toggled</div>
<div class="toggle-button-2">Button 2 toggled</div>
<div class="toggle-button-3">Button 3 toggled</div>

标签： javascripthtmlcss

解决方案

编码的“正确”方式：

const toggleButtons = document.querySelector('#toggle-buttons')

document.querySelector('#buttons').onclick = ({target}) =>
  {
  if (!target.matches('div[data-button]')) return

  let actualButton = toggleButtons.className
    , targetButton = target.dataset.button
    ;
  toggleButtons.className = (actualButton===targetButton) 
                          ?  '' 
                          : targetButton
  }
.flex {
  display : flex;
  }
#buttons > div[data-button] {
  background-color : red;
  color            : white;
  padding          : 10px 20px;
  }
#toggle-buttons > div { 
  display : none;
  }
#toggle-buttons.b1 > .toggle-button-1,
#toggle-buttons.b2 > .toggle-button-2, 
#toggle-buttons.b3 > .toggle-button-3 { 
  display : flex;
  }
<div id="buttons" class="flex">
  <div data-button="b1" > Button1 </div>
  <div data-button="b2" > Button2 </div>
  <div data-button="b3" > button3 </div>
</div>

<div id="toggle-buttons"> 
  <div class="toggle-button-1">Button 1 toggled</div>
  <div class="toggle-button-2">Button 2 toggled</div>
  <div class="toggle-button-3">Button 3 toggled</div>
</div>

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