首页 > 解决方案 > 纸牌问题,C 函数有问题

问题描述

我只是一个初学者,非常感谢您的帮助。在下面的代码中,我收到错误,似乎我对函数做错了。程序输出如下所示,它假设随机生成一个列表,如图所示。

请提供有关如何修复此程序的任何建议。


#include <stdio.h>

void random_shuffle(deck, deck+52)   {
    
}

/* initialize suit array */
const char *suit[ 4 ] = { "Hearts", "Diamonds", "Clubs", "Spades" };
/* initialize face array */
const char *face[ 13 ] = { "Ace", "Deuce", "Three", "Four",
                           "Five", "Six", "Seven", "Eight",
                           "Nine", "Ten", "Jack", "Queen", "King" };

void for_each(int *start, int *end, void(*f)(int)) {
    for (int *cur = start; cur < end; cur++) {
        f(*cur);
    }
    
    
    
}

void print_card(int n) {
    printf("%s of %s\n", face[n % 13], suit[n / 13]);
}

void shuffleAndDeal( int workdeck[][ 13 ], const char *workface[], const char *worksuit[] ) {
//  srand((unsigned int)time(NULL));

    int deck[52];

    // Prime, shuffle, dump
    for (int i=0;i<52;i++) {
        deck[i] = i;
    }
    random_shuffle(deck, deck+52);
    for_each(deck, deck+52, print_card);
    return;
}

int main( int argc, char *argv[] ) {
/* initialize deck array */
    int deck[ 4 ][ 13 ] = { 0 };
    shuffleAndDeal( deck, face, suit );
    return 0; /* indicates successful termination */
} 

[![输出][1]][1]

以下是我遇到的错误

 void random_shuffle(deck, deck+52)   {
                               ^
main.c: In function ‘shuffleAndDeal’:
main.c:36:5: warning: implicit declaration of function ‘random_shuffle’ [-Wimplicit-function-declaration]
     random_shuffle(deck, deck+52);
     ^~~~~~~~~~~~~~
main.c: At top level:
main.c:47:6: error: expected ‘=’, ‘,’, ‘;’, ‘asm’ or ‘__attribute__’ before ‘:’ token
https://www.onlinegdb.com/online_c_compiler#tab-stdin
      ^```


  [1]: https://i.stack.imgur.com/bF7tl.png

标签: c

解决方案


这个 ...

void random_shuffle(deck, deck+52)   {

}

... 不是有效的 C 函数定义。您必须为每个函数参数表达一个类型和一个不同的标识符。您没有为任一参数指定类型,并且deck+52不是(仅)标识符。


推荐阅读