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java - TimePickerDialog 构造函数问题

问题描述

if (v == btnEndTimePicker) {

            final Calendar c = Calendar.getInstance() ;
            mHour = c.get(Calendar.HOUR_OF_DAY);
            mMinutes = c.get(Calendar.MINUTE);
            TimePickerDialog timePickerDialog = new TimePickerDialog(true, this,
                    (view, hour, minutes) -> {
                        return editStartTime.setText((hour + ":" + minutes), mHour, mMinutes);
                    });
            timePickerDialog.show();
        }
        if (v == btnStartTimePicker) {

            final Calendar c = Calendar.getInstance() ;
            sHour = c.get(Calendar.HOUR_OF_DAY);
            sMinutes = c.get(Calendar.MINUTE);
            CalendarDialog timePickerDialog = new CalendarDialog(true, this,
                    (view, hour, minutes) -> {
                        return editStartTime.setText((hour + ":" + minutes), sHour, sMinutes);
                    });
            timePickerDialog.show();
        }

我不确定在这里做什么，我使用类似的代码弹出日历日期对话框并选择一个日期，然后将其放入 EditText 字段。当我为 TimePickerDialog 执行此操作时，它说它期待一个 char[] 而不是一个字符串。

标签： javaandroidtimepickerdialog

解决方案

你给 TimePickerDialog 对象提供了错误的参数

     public TimePickerDialog (Context context,  
            TimePickerDialog.OnTimeSetListener listener, 
            int hourOfDay, 
            int minute, 
            boolean is24HourView)

替换这个

  TimePickerDialog timePickerDialog = new TimePickerDialog(true, this,
                (view, hour, minutes) -> {
                    return editStartTime.setText((hour + ":" + minutes), mHour, mMinutes);
                });

和

TimePickerDialog timePickerDialog = new TimePickerDialog(this,listener,2,25,true);

这些是正确的参数，更多检查一下

https://developer.android.com/reference/android/app/TimePickerDialog

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