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php - 如何在 1 个域上提供两个 laravel 应用程序？

问题描述

我有两个这样的 laravel 应用程序：

  - apps
      - dashboard
      - website

我试图在 linux 机器上为它们服务，我似乎无法让它们一起工作。我想要两个这样的网址： https ://test.example.co

https://test.example.co/dashboard

server {
  server_name test.example.co;
  index index.php index.html index.htm index.nginx-debian.html;

  location = / {
       root /var/www/example/apps/website;
       try_files $uri $uri/ /public/index.php;
  }

  location ~ ^/dashboard  {
       root /var/www/example/apps;
       try_files $uri $uri/ /dashboard/public/index.php;
       #try_files $uri $uri/ /index.html;
  }

  location ~ \.php$ {
     include snippets/fastcgi-php.conf;
     fastcgi_pass unix:/run/php/php7.4-fpm.sock;
  }

  location ~ /\.ht {
     deny all;
  }

    listen [::]:443 ssl ipv6only=on; # managed by Certbot
    listen 443 ssl; # managed by Certbot
    ssl_certificate /etc/letsencrypt/live/test.example.co/fullchain.pem; # managed by Certbot
    ssl_certificate_key /etc/letsencrypt/live/test.example.co/privkey.pem; # managed by Certbot
    include /etc/letsencrypt/options-ssl-nginx.conf; # managed by Certbot
    ssl_dhparam /etc/letsencrypt/ssl-dhparams.pem; # managed by Certbot

    # pass the PHP scripts to FastCGI server listening on /var/run/php7.4-fpm.sock
    location ~ \.php$ {
            try_files $uri /index.php =404;
            fastcgi_pass unix:/var/run/php/php7.4-fpm.sock;
            fastcgi_index index.php;
            fastcgi_param SCRIPT_FILENAME $document_root$fastcgi_script_name;
            include fastcgi_params;
    }

}
server {
    if ($host = test.example.co) {
        return 301 https://$host$request_uri;
    } # managed by Certbot
}

标签： phplinuxlaravelnginxserver

解决方案

如果您像这样编写代码，您能告诉我结果是什么：

  location ~ ^/dashboard  {
       root /var/www/example/apps/dashboard/public;
       try_files $uri $uri/ /index.php;
  }
  location = ~ ^/ {
       root /var/www/example/apps/website/public;
       try_files $uri $uri/ /index.php;
  }

我只是交换它。因此它将搜索仪表板，如果用户不在仪表板中，它将检查根目录。

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