reactjs - 在 params 中传递函数时,在导航状态中发现了不可序列化的值
问题描述
我有两个屏幕:
屏幕 A
import React, { useState } from "react";
import { Text, View, Button } from "react-native";
const ViewA = ({ navigation }) => {
const [val, setVal] = useState(null);
const [val2, setVal2] = useState(null);
const callBack = (value1,value2) => {
setVal(value1);
setVal2(value2);
};
const onNextPress = () => {
navigation.navigate("Second Screen", { callBack: callBack });
};
return (
<View>
<Text>{val}{val2}</Text>
<Button title="Next" onPress={onNextPress} />
</View>
);
};
export default ViewA;
屏幕 B
import React from "react";
import { View, Button } from "react-native";
const ViewB = ({ route, navigation }) => {
const onBackPress = () => {
const { callBack } = route.params;
callBack(5,6); // Your new value to set
navigation.goBack();
};
return (
<View>
<Button title="back" onPress={onBackPress} />
</View>
);
};
export default ViewB;
当我进入屏幕 B 时,出现警告:在导航状态下发现了不可序列化的值。我该如何解决?
解决方案
如果您在 params 中传递类实例、函数等不可序列化的值,则可能会发生这种情况。在这种情况下,React Navigation 会警告您,因为这可能会破坏其他功能,例如状态持久性、深度链接等。
...
如果您不使用状态持久性或深度链接到接受参数中的函数的屏幕,则警告不会影响您,您可以放心地忽略它。要忽略警告,您可以使用
YellowBox.ignoreWarnings
.
import { YellowBox } from 'react-native';
YellowBox.ignoreWarnings([
'Non-serializable values were found in the navigation state',
]);
另一种方法是将状态移动到路由参数而不是本地状态ViewA
(这意味着您可以在导航时设置它):
import React, {useState, useEffect} from 'react';
import { Text, View, Button } from 'react-native';
import { NavigationContainer } from '@react-navigation/native';
import { createStackNavigator } from '@react-navigation/stack';
const Stack = createStackNavigator();
const ViewA = ({ route, navigation }) => {
const onNextPress = () => {
navigation.navigate("ViewB", {
previousScreen: route.name
});
};
return (
<View>
<Text>ViewA</Text>
<Text>Params: {JSON.stringify(route.params)}</Text>
<Button title="Next" onPress={onNextPress} />
</View>
);
};
const ViewB = ({ route, navigation }) => {
const onBackPress = () => {
navigation.navigate(route.params.previousScreen, {
val: 5,
val2: 6,
})
};
return (
<View>
<Text>ViewB</Text>
<Text>Params: {JSON.stringify(route.params)}</Text>
<Button title="back" onPress={onBackPress} />
</View>
);
};
export default function App() {
return (
<NavigationContainer>
<Stack.Navigator mode="modal">
<Stack.Screen name="ViewA" component={ViewA} />
<Stack.Screen name="ViewB" component={ViewB} />
</Stack.Navigator>
</NavigationContainer>
);
}