python - 计数器 - 跳过元素并且在 for 循环期间不增加

Question

所以我正在为我的班级编写一个基本的登录系统，并且我正在使用 for 循环和计数器来线性搜索列表。但是，当我输入一个应该正确的用户名时，它返回为未经授权的。我已经尝试在循环的每次传递之间打印计数器，我发现即使范围是（0,6）它最多只能计数三个？

代码、shell 和错误消息的图像

import random

userver = 0
userList = ["Arabella12", "Constance01", "Hugo11", "James09", "Jane12", "Max06", "Ted04"]
pwrdList = ["bella12", "1234", "HGWel!", "j@me£S", "Password", "notpassword", "ted4"]
found = False
pfound = False

def login():
    username = input("Type in your username ")
    index1 = 0
    wrong = 0
    found = False
    c3 = 0
    print("index one before c3 loop=", index1)  #delete after testing
    for c3 in range(0, 6): #username check counter
        if username == userList[c3]:  #if username is found with the counter c3
            found = True  #making the key for the next part of the code true
            index = s(c3)
            print(index," is the index")
            c3 = c3 + 1
            break
        elif found == False:
            print("c3: ", c3)  #checking counter- delete after debugging
            print("unauthorised user...attempting again")  #if username isnt present
            c3 = c3 + 1  #upping the counter
            exit

login()

标签： pythonarraysfor-loopcounterlinear-search

Answer 1