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python-3.x - 如何使用 Boto 3 显示 EC2 实例名称

问题描述

我正在使用下面的代码来显示 instance_id,instance_type 但我无法显示我想要的实例名称

print (instance.id, instance.instance_type, region)这是有效的，但这不是 instance.instance_name

import boto3
access_key = "AKIAJ5G2FAUVO3TXXXXXXXX"
secret_key = "nk7eytkWfoSDU0GwvBZVawQvXXXXXX"
client = boto3.client('ec2', aws_access_key_id=access_key, aws_secret_access_key=secret_key,region_name='us-east-1')
ec2_regions = [region['RegionName'] for region in client.describe_regions()['Regions']]
for region in ec2_regions:
                conn = boto3.resource('ec2', aws_access_key_id=access_key, aws_secret_access_key=secret_key,region_name=region)
                instances = conn.instances.filter()
                for instance in instances:
                    if instance.state["Name"] == "running":
                        print (instance.instance_name,instance.id, instance.instance_type, region)

标签： python-3.xamazon-web-servicesamazon-ec2boto3boto

解决方案

您正在使用的对象没有instance名称属性。原因是实例的“名称”仅基于名为Name. 所以你必须得到标签，并找到一个标签名称Name：

def get_tag(tags, key='Name'):

  if not tags: return ''

  for tag in tags:
  
    if tag['Key'] == key:
      return tag['Value']
    
  return ''

ec2_regions = [region['RegionName'] for region in client.describe_regions()['Regions']]

for region in ec2_regions:
    conn = boto3.resource('ec2', aws_access_key_id=access_key, aws_secret_access_key=secret_key,region_name=region)
    instances = conn.instances.filter()
    for instance in instances:
        instance_name = get_tag(instance.tags)        
        print (instance_name, instance.id, instance.instance_type, region)

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