java - 如何从给定的 IPAddress 打印所有子网？

Question

这是我的输出。

    run: Enter the IP address:192.32.4.1
     IP in binary is 11000000001000000000010000000001 
    Enter the number of addresses:64
     Number of bits required for address =6 
    The subnet mask is = 26 
    First address is = 192.32.4.0 Last address is = 192.32.4.63 BUILD SUCCESSFUL (total time: 14 seconds)

我想打印 和 之间的所有First address is = 192.32.4.0子网Last address is = 192.32.4.255。

我尝试了 for 循环，但我也没有得到。

谁能在这段代码中帮助我如何通过打印所有子网来改进这段代码？

我在打印所有子网时遇到了困难，但我很努力，但没有得到它们。

这是我的代码：

import java.util.Scanner;

public class JavaApplication6 {

    public static void main(String[] args) {
        // TODO code application logic here

        Scanner sc = new Scanner(System.in);
        System.out.print("Enter the ip address:");
        String ip = sc.nextLine();
        String split_ip[] = ip.split("\\."); // SPlit the string after every .
        String split_bip[] = new String[4]; // split binary ip
        String bip = "";
        for (int i = 0; i < 4; i++) {
            // “18” => 18 => 10010 => 00010010
            split_bip[i] = appendZeros(Integer.toBinaryString(Integer.parseInt(split_ip[i])));
            bip += split_bip[i];
        }
        System.out.println("IP in binary is " + bip);
        System.out.print("Enter the number of addresses:");
        int n = sc.nextInt();

        // Calculation of mask
        /*
         * eg if address = 120, log 120/log 2 gives log to the base 2 => 6.9068, ceil
         * gives us upper integer
         */
        int bits = (int) Math.ceil(Math.log(n) / Math.log(2));
        System.out.println("Number of bits required for address =" + bits);
        int mask = 32 - bits;
        System.out.println("The subnet mask is = " + mask);

        // Calculation of first address and last address

        // String fip[] = {"","","",""};

        int fbip[] = new int[32];
        for (int i = 0; i < 32; i++)
            fbip[i] = (int) bip.charAt(i) - 48; // convert cahracter 0,1 to integer 0,1
        for (int i = 31; i > 31 - bits; i--) // Get first address by ANDing last n bits with 0
            fbip[i] &= 0;
        String fip[] = { "", "", "", "" };
        for (int i = 0; i < 32; i++)
            fip[i / 8] = new String(fip[i / 8] + fbip[i]);
        System.out.print("First address is = ");
        for (int i = 0; i < 4; i++) {
            System.out.print(Integer.parseInt(fip[i], 2));
            if (i != 3)
                System.out.print(".");
        }
        System.out.println();

        int lbip[] = new int[32];
        for (int i = 0; i < 32; i++)
            // convert cahracter 0,1 to integer 0,1
            // for(int i=31;i>31-bits;i–){ //Get last address by ORing last n bits with 1
            for (int i = 31; i > 31 - bits; i--)
                lbip[i] = (int) bip.charAt(i) - 48;
        lbip[i] |= 1;
        String lip[] = { "", "", "", "" };
        for (int i = 0; i < 32; i++)
            lip[i / 8] = new String(lip[i / 8] + lbip[i]);
        System.out.print("Last address is = ");
        for (int i = 0; i < 4; i++) {
            System.out.print(Integer.parseInt(lip[i], 2));
            if (i != 3)
                System.out.print(".");
        }
        System.out.println();
    }

    static String appendZeros(String s) {
        String temp = new String("00000000");
        return temp.substring(s.length()) + s;
    }
}

标签： javaip-addresssubnet