regex - 删除字符串直到第一次出现右括号

Question

我有一个看起来像的文件：

[----------] 7 tests from RouteGenSetup
[ RUN      ] RouteGenSetup.AcceptTATTest
[2021-03-08 22:55:53.937] [info] TimeSlotAssignmentTable::LogTATRow(Add): 1.1 -> 2.1, rounds: LLLLLL, pattern: TR
[2021-03-08 22:55:53.937] [info] TimeSlotAssignmentTable::LogTATRow(Add): 1.1 -> 5.1, rounds: LLLLLL, pattern: TR
[2021-03-08 22:55:53.937] [info] TimeSlotAssignmentTable::LogTATRow(Add): 6.1 -> 7.1, rounds: LLLLLL, pattern: TR
[       OK ] RouteGenSetup.AcceptTATTest (0 ms)
[ RUN      ] RouteGenSetup.BlockLinksTest
[2021-03-08 22:55:53.937] [error] TimeSlotAssignmentTable::LogTATRow(Add): 1.1 -> 2.1, rounds: LLLLLL, pattern: TR
[2021-03-08 22:55:53.938] [error] TimeSlotAssignmentTable::LogTATRow(Add): 1.1 -> 5.1, rounds: LLLLLL, pattern: TR

我想摆脱日期和时间戳（例如，[2021-03-08 22:55:53.937]）。为此，我尝试使用以下sed命令：

sed -i '/^\[2021-/s/^.*\]\ //1' output.txt

但是，时间戳右侧的[info]或括号也会被删除：[error]

[----------] 7 tests from RouteGenSetup
[ RUN      ] RouteGenSetup.AcceptTATTest
TimeSlotAssignmentTable::LogTATRow(Add): 1.1 -> 2.1, rounds: LLLLLL, pattern: TR
TimeSlotAssignmentTable::LogTATRow(Add): 1.1 -> 5.1, rounds: LLLLLL, pattern: TR
TimeSlotAssignmentTable::LogTATRow(Add): 6.1 -> 7.1, rounds: LLLLLL, pattern: TR
[       OK ] RouteGenSetup.AcceptTATTest (0 ms)
[ RUN      ] RouteGenSetup.BlockLinksTest
TimeSlotAssignmentTable::LogTATRow(Add): 1.1 -> 2.1, rounds: LLLLLL, pattern: TR
TimeSlotAssignmentTable::LogTATRow(Add): 1.1 -> 5.1, rounds: LLLLLL, pattern: TR

当我尝试

sed -i '/^\[2021/s/[^\]]*//' output.txt

第一个左括号删除而不是第一个右括号：

[----------] 7 tests from RouteGenSetup
[ RUN      ] RouteGenSetup.AcceptTATTest
2021-03-08 22:55:53.937] [info] TimeSlotAssignmentTable::LogTATRow(Add): 1.1 -> 2.1, rounds: LLLLLL, pattern: TR
2021-03-08 22:55:53.937] [info] TimeSlotAssignmentTable::LogTATRow(Add): 1.1 -> 5.1, rounds: LLLLLL, pattern: TR
2021-03-08 22:55:53.937] [info] TimeSlotAssignmentTable::LogTATRow(Add): 6.1 -> 7.1, rounds: LLLLLL, pattern: TR
[       OK ] RouteGenSetup.AcceptTATTest (0 ms)
[ RUN      ] RouteGenSetup.BlockLinksTest
2021-03-08 22:55:53.937] [error] TimeSlotAssignmentTable::LogTATRow(Add): 1.1 -> 2.1, rounds: LLLLLL, pattern: TR
2021-03-08 22:55:53.938] [error] TimeSlotAssignmentTable::LogTATRow(Add): 1.1 -> 5.1, rounds: LLLLLL, pattern: TR

并尝试

sed -i '/^\[2021/s/^[^\]]*\]//' output.txt

不产生任何变化。我不知道如何解决这个问题。我尝试了一些类似帖子中推荐的东西，但没有运气。

注意：这不是sed - Linux 中正则表达式方括号检测]的重复，因为这里的问题有所不同：如果该行以某个前缀开头，则仅匹配字符串开头和第一个 + 空格之间的子字符串。

sed 在以特定模式开头的行中替换单词 using没有解释如何获取以特殊字符开头的行，然后从开始到第一个]+ 空格匹配字符串。

标签： regexsedreplaceposix

Answer 1

您可以使用

sed -i '/^\[2021-/s/^[^]]*] //' file

这里，

• /^\[2021-/- 查找以开头的行[2021-
• s/^[^]]*] //- 匹配任何零个或多个字符，而不是]从字符串的开头到第一个字符]，然后是空格，并删除这些匹配项（因为 RHS 为空）。

Note[^]]是一个否定括号表达式，它匹配除 . 之外的任何字符]。由于括号表达式不支持正则表达式转义序列，]需要是括号表达式中的第一个字符，因此不能\]在括号表达式中使用 anwhere。

查看在线演示：

s='[----------] 7 tests from RouteGenSetup
[ RUN      ] RouteGenSetup.AcceptTATTest
[2021-03-08 22:55:53.937] [info] TimeSlotAssignmentTable::LogTATRow(Add): 1.1 -> 2.1, rounds: LLLLLL, pattern: TR
[2021-03-08 22:55:53.937] [info] TimeSlotAssignmentTable::LogTATRow(Add): 1.1 -> 5.1, rounds: LLLLLL, pattern: TR
[2021-03-08 22:55:53.937] [info] TimeSlotAssignmentTable::LogTATRow(Add): 6.1 -> 7.1, rounds: LLLLLL, pattern: TR
[       OK ] RouteGenSetup.AcceptTATTest (0 ms)
[ RUN      ] RouteGenSetup.BlockLinksTest
[2021-03-08 22:55:53.937] [error] TimeSlotAssignmentTable::LogTATRow(Add): 1.1 -> 2.1, rounds: LLLLLL, pattern: TR
[2021-03-08 22:55:53.938] [error] TimeSlotAssignmentTable::LogTATRow(Add): 1.1 -> 5.1, rounds: LLLLLL, pattern: TR'
sed '/^\[2021-/s/^[^]]*] //' <<< "$s"

输出：

[----------] 7 tests from RouteGenSetup
[ RUN      ] RouteGenSetup.AcceptTATTest
[info] TimeSlotAssignmentTable::LogTATRow(Add): 1.1 -> 2.1, rounds: LLLLLL, pattern: TR
[info] TimeSlotAssignmentTable::LogTATRow(Add): 1.1 -> 5.1, rounds: LLLLLL, pattern: TR
[info] TimeSlotAssignmentTable::LogTATRow(Add): 6.1 -> 7.1, rounds: LLLLLL, pattern: TR
[       OK ] RouteGenSetup.AcceptTATTest (0 ms)
[ RUN      ] RouteGenSetup.BlockLinksTest
[error] TimeSlotAssignmentTable::LogTATRow(Add): 1.1 -> 2.1, rounds: LLLLLL, pattern: TR
[error] TimeSlotAssignmentTable::LogTATRow(Add): 1.1 -> 5.1, rounds: LLLLLL, pattern: TR