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python - 将图形从字典形式转换为python中的矩阵

问题描述

{'x050412_1_0000_1_4'：{'0-4'：64.951658696839，'2-3'：47.573389284767174，'1-2 ': 65.07665932728878, '1-3': 58.326301639483376, '3-4': 42.477331382632784, '1-4': 47.380533137671634, '2-4': 18.995337464493748}, 'X050412_1_0000_1_5': {'0-4': 74.45548880223673, '2-3': 42.921786085506746, '1-2': 22.297921437434468, '0-1': 16.755486281812296, '0-2': 31.640265835324445, '0-3': 49.53140665618129, '1-3': 55.29908155494086, '3 -4'：25.4227462686469，'1-4'：78.22578893907047，'2-4'：61.7341951054909}1-2'：26.33647295558006，'0-1'：27.165619713343553，'0-2'：53.21604990987211，'0-3'：31.97262626262680029007，1340029007， 4': 33.294628738732015, '2-4': 23.60048014617499}} 假设我有一个像这样表示的图，我想创建将其转换为矩阵形式。

标签： pythongraph

解决方案

for k,v in dataset.distances.items():
if k not in diz2:
    diz2[k] = {}
for k2,v2 in v.items():
    res = tuple(map(int, k2.split('-')))
    if res not in diz2:
        diz2[k][res] = v2

def convert(diz5):
temp_x = max([cord[0] for cord in diz5.keys()])
temp_y = max([cord[1] for cord in diz5.keys()])
res2 = [[0] * (temp_y + 1) for ele in range(temp_x + 1)]
for (i, j), val in diz5.items():
    res2[i][j] = val
#print("The dictionary after creation of Matrix : " + str(res2))
return  res2

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