List<ShipInventoryReportDataVO> lstShipInvData = shipInventoryReportDAO
    .getShippableInventoryReportData(inpu,java,arrays,sorting,object,collections"/>
	














    

		

        

            
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首页  > 解决方案 > 排序列表 numerically and alphabetically using Object product field

List<ShipInventoryReportDataVO> lstShipInvData = shipInventoryReportDAO
    .getShippableInventoryReportData(inpu












java - 排序列表 numerically and alphabetically using Object product field

List<ShipInventoryReportDataVO> lstShipInvData = shipInventoryReportDAO
    .getShippableInventoryReportData(inpu





问题描述



List<ShipInventoryReportDataVO> lstShipInvData = shipInventoryReportDAO
    .getShippableInventoryReportData(inputVO, true);



ShipInventoryReportDataVO is my object class and getting the data from a stored procedure. In ShipInventoryReportDataVO object class I have a field called productCode and the data of productCode will in alphanumeric like


0123, 
654, 
sparem, 
3205, 
the wholeland, 
10, 
1. 



when I am sorting the productCode which is in object class, I am getting the output as


0123
1
10
3205
654
sparem
wholeland.



this is the code I tried to sort


List<ShipInventoryReportDataVO> lstShipInvData = shipInventoryReportDAO.getShippableInventoryReportData(inputVO, true);
                
Collections.sort(lstShipInvData, 
    (o1, o2) -> 
        (o1.getProductCode().compareTo(o2.getProductCode()))
);



and this


lstShipInvData = (List) lstShipInvData.stream()
        .sorted(Comparator.comparing(
            ShipInventoryReportDataVO::getProductCode
        ))
        .collect(Collectors.toList());



both the codes gets output as above


but I need the output as below


1
10
654
0123
3205
sparem
wholeland



This is the code which i tried now


List<ShipInventoryReportDataVO> productCodes = shipInventoryReportDAO.getShippableInventoryReportData(inputVO, true);

Comparator<String> byProductCode = Comparator.comparingInt(String::length)
                        .thenComparing(Comparator.naturalOrder());

productCodes.sort(Comparator.comparing(
                        ShipInventoryReportDataVO::getProductCode, byProductCode
));

productCodes.forEach(System.out::println);
System.out.println(productCodes.toString());










You can wrap your query in set;


distinct() does not go well with values() as per documentation


ip_sets = set(Comment.objects.order_by().values('ip_address'))
ip_list = list(set(Comment.objects.order_by().values('ip_address')))



标签： javaarrayssortingobjectcollections


解决方案









预期的输出显示数据应首先按产品代码的长度排序，然后按字母顺序排序。


这可以通过链接比较器和使用来实现Comparator.comparing(Function<? super T,? extends U> keyExtractor, <? super U> keyComparator)：


List<ShipInventoryReportDataVO> productCodes = Arrays.asList(
        new ShipInventoryReportDataVO("0123"),
        new ShipInventoryReportDataVO("654"),
        new ShipInventoryReportDataVO("sparem"),
        new ShipInventoryReportDataVO("3205"),
        new ShipInventoryReportDataVO("the wholeland"),
        new ShipInventoryReportDataVO("10"),
        new ShipInventoryReportDataVO("1")
);

Comparator<String> byProductCode = Comparator.comparingInt(String::length)
    .thenComparing(Comparator.naturalOrder());

productCodes.sort(Comparator.comparing(
    ShipInventoryReportDataVO::getProductCode, byProductCode
));

productCodes.forEach(System.out::println);



输出


1
10
654
0123
3205
sparem
the wholeland











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