首页 > 解决方案 > 将 MediaItem 列表转换为 ConcatenatingAudioSource 错误:“ConcatenatingAudioSource”实例

问题描述

我正在尝试将列表解析/转换MediaItem为 a ConcatenatingAudioSource,但我的单元测试不断给我一个错误,即转换ConcatenatingAudioSource后的与目标源不匹配。我的测试是

List<MediaItem> audioSource = <MediaItem>[
      MediaItem(
        // This can be any unique id, but we use the audio URL for convenience.
        id: "https://s3.amazonaws.com/scifri-episodes/scifri20181123-episode.mp3",
        album: "Science Friday",
        title: "A Salute To Head-Scratching Science",
        artist: "Science Friday and WNYC Studios",
        duration: Duration(milliseconds: 5739820),
        artUri: Uri.parse(
            "https://media.wnyc.org/i/1400/1400/l/80/1/ScienceFriday_WNYCStudios_1400.jpg"),
      ),
      MediaItem(
        id: "https://s3.amazonaws.com/scifri-segments/scifri201711241.mp3",
        album: "Science Friday",
        title: "From Cat Rheology To Operatic Incompetence",
        artist: "Science Friday and WNYC Studios",
        duration: Duration(milliseconds: 2856950),
        artUri: Uri.parse(
            "https://media.wnyc.org/i/1400/1400/l/80/1/ScienceFriday_WNYCStudios_1400.jpg"),
      ),
];

test('mediaItem2ConcatenatingAudioSource test', () {
      expect(
        // Here's where the conversion happens
        ConcatenatingAudioSource(
          children: audioSource
              .map((item) => AudioSource.uri(Uri.parse(item.id)))
              .toList(),
        ),
        ConcatenatingAudioSource(children: [
          AudioSource.uri(Uri.parse(
              'https://s3.amazonaws.com/scifri-episodes/scifri20181123-episode.mp3')),
          AudioSource.uri(Uri.parse(
              "https://s3.amazonaws.com/scifri-segments/scifri201711241.mp3")),
        ]),
      );
});

我得到的错误如下。我相信这是在说两者ConcatenatingAudioSource不一样,它们应该在哪里。

Expected: <Instance of 'ConcatenatingAudioSource'>
  Actual: <Instance of 'ConcatenatingAudioSource'>

我从字面上复制了audio_service示例中的转换部分(第 362 行),所以我真的很困惑这里出了什么问题。(当我的实际应用程序运行时,此转换代码也不起作用。我将actual测试的一部分放在setSource()方法 thenplay()中,但没有任何反应。)

任何帮助,将不胜感激!谢谢!

标签: flutterdartjust-audio

解决方案


just_audio 不认为两个音频源是相等的,即使它们包含相同的元数据。这是因为每个副本都有自己的内部缓冲区和不同的内部状态。

您所能做的就是检查音频源中元数据的相等性。例如比较播放列表ab

ConcatenatingAudioSource a = ...;
ConcatenatingAudioSource b = ...;

expect(
  a.children.map((s) => (s as UriAudioSource).uri).toList(),
  b.children.map((s) => (s as UriAudioSource).uri).toList(),
);

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