首页 > 解决方案 > 我如何在 tkinter 中创建一组带有循环的按钮?

问题描述

我有这个程序我正在尝试创建,基本上我需要在 tkinter 中制作 8 行按钮,但我不知道如何使用循环来做到这一点,没有循环我这样做了:

def decimal():
app = Toplevel(root)
app.title("Traducteur décimal")
app.geometry("400x200")
r1 = Button(app, text="LED 1 ON")
r2 = Button(app, text="LED 1 OFF")
r1.place(x=125,y=0)
r2.place(x=225,y=0)
r3 = Button(app, text="LED 2 ON")
r4 = Button(app, text="LED 2 OFF")
r3.place(x=125, y=40)
r4.place(x=225, y=40)
r5 = Button(app, text="LED 3 ON")
r6 = Button(app, text="LED 3 OFF")
r5.place(x=125, y=80)
r6.place(x=225, y=80)

顺便说一句,我很抱歉英语不好。谢谢

标签: pythontkinterbutton

解决方案


一种方法是将它们全部放在一个循环中list。作为一个列表,你可以通过索引访问它的元素:2-tuplesfor

buttons = []

x_loc_on, x_loc_off = (125, 225)

y_start = 0
y_offset = 40

commands = [<16 functions here>]

for row in range(8):
    # calculate the pair's y-position based on row
    y_pos_of_row = y_start + row * y_offset

    # get the row number (starts from 1 unlike the variable `row`; so adding 1)
    row_number = row + 1

    # generate the ON button
    button_1 = Button(app, text=f"LED {row_number} ON", command=commands[row])
    button_1.place(x=x_loc_on, y=y_pos_of_row)

    # generate the OFF button
    button_2 = Button(app, text=f"LED {row_number} OFF", command=commands[row+1])
    button_2.place(x=x_loc_off, y=y_pos_of_row)

    # put this row's ON-OFF button pair as a 2-tuple into a list
    buttons.append((button_1, button_2))

然后,您可以通过 访问i行和ON按钮,buttons[i][0]并通过 访问同一行OFF按钮buttons[i][1]


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