directx - 如何将 RTV 输出复制到立方体贴图的一侧?
问题描述
我目前正在我的游戏引擎中实现漫反射( PBR的基于图像的闪电的一部分) 。我到了必须拍摄HDR图像并将其转换为立方体贴图的地步。我目前正在使用 EquirectangularToCubemap 着色器,它工作正常。我能够将 HDR 图像投影到(单位)立方体。现在到了我被卡住的部分,我不能把这个立方体变成一个立方体贴图。我尝试使用1 个 TextureCube、6 个 RenderTargetView和一个ShaderResourceView。我的计划是使用FOV从不同的视图投影中渲染(单位)立方体 6 次90 来捕获每个渲染目标中的整个边,最后将渲染目标的每个输出复制到纹理立方体的对应边。我不知道如何做到这一点^。
注意:我使用 DirextX11 作为渲染后端。这是关于我的问题的伪代码(不起作用)
glm::mat4 captureProjection = glm::perspective(glm::radians(90.0f), 1.0f, 0.1f, 10.0f);
glm::mat4 captureViews[] =
{
glm::lookAt(glm::vec3(0.0f, 0.0f, 0.0f), glm::vec3(1.0f, 0.0f, 0.0f), glm::vec3(0.0f, -1.0f, 0.0f)),
glm::lookAt(glm::vec3(0.0f, 0.0f, 0.0f), glm::vec3(-1.0f, 0.0f, 0.0f), glm::vec3(0.0f, -1.0f, 0.0f)),
glm::lookAt(glm::vec3(0.0f, 0.0f, 0.0f), glm::vec3(0.0f, 1.0f, 0.0f), glm::vec3(0.0f, 0.0f, 1.0f)),
glm::lookAt(glm::vec3(0.0f, 0.0f, 0.0f), glm::vec3(0.0f, -1.0f, 0.0f), glm::vec3(0.0f, 0.0f, -1.0f)),
glm::lookAt(glm::vec3(0.0f, 0.0f, 0.0f), glm::vec3(0.0f, 0.0f, 1.0f), glm::vec3(0.0f, -1.0f, 0.0f)),
glm::lookAt(glm::vec3(0.0f, 0.0f, 0.0f), glm::vec3(0.0f, 0.0f, -1.0f), glm::vec3(0.0f, -1.0f, 0.0f))
};
//Create the TextureCube
D3D11_TEXTURE2D_DESC textureDesc = {};
textureDesc.Width = 512;
textureDesc.Height = 512;
textureDesc.MipLevels = 1;
textureDesc.ArraySize = 6;
textureDesc.Format = DXGI_FORMAT_R32G32B32A32_FLOAT;
textureDesc.CPUAccessFlags = 0;
textureDesc.SampleDesc.Count = 1;
textureDesc.SampleDesc.Quality = 0;
textureDesc.Usage = D3D11_USAGE_DEFAULT;
textureDesc.BindFlags = D3D11_BIND_SHADER_RESOURCE | D3D11_BIND_RENDER_TARGET;
textureDesc.MiscFlags = D3D11_RESOURCE_MISC_TEXTURECUBE;
ID3D11Texture2D* tex = nullptr;
DX_CALL(DX11Internal::GetDevice()->CreateTexture2D(&textureDesc, nullptr, &tex));
// Create the Shader Resource view for the texture cube
D3D11_SHADER_RESOURCE_VIEW_DESC srvDesc = {};
srvDesc.Format = textureDesc.Format;
srvDesc.ViewDimension = D3D11_SRV_DIMENSION_TEXTURECUBE;
srvDesc.Texture2D.MostDetailedMip = 0;
srvDesc.Texture2D.MipLevels = 1;
DX_CALL(DX11Internal::GetDevice()->CreateShaderResourceView(tex, &srvDesc, &mSRV));
//Create the Render target views
Vector<ID3D11RenderTargetView*> rtvs;
for (Uint i = 0; i < 6; i++)
{
D3D11_RENDER_TARGET_VIEW_DESC renderTargetViewDesc = {};
renderTargetViewDesc.Format = textureDesc.Format;
renderTargetViewDesc.ViewDimension = D3D11_RTV_DIMENSION_TEXTURE2D;
renderTargetViewDesc.Texture2D.MipSlice = 0;
ID3D11RenderTargetView* view = nullptr;
DX11Internal::GetDevice()->CreateRenderTargetView(tex, &renderTargetViewDesc, &view);
rtvs.push_back(view);
}
tex->Release();
auto deviceContext = DX11Internal::GetDeviceContext();
for (Uint i = 0; i < 6; ++i)
{
float clearColor[4] = { 1.0f, 0.1f, 0.1f, 1.0f };
deviceContext->ClearRenderTargetView(rtvs[i], clearColor);
Vault::Get<Shader>("EquirectangularToCubemap.hlsl")->Bind();
auto data = captureProjection * captureViews[i];
cbuffer->Bind();
cbuffer->SetData(&data);
texture->Bind(0);
tempPipeline->Bind();
deviceContext->OMSetRenderTargets(1, &rtvs[i], nullptr);
//I am rendering the cube here from different view projection to capture the faces, but I dont't know where to copy the data to the //side of the TextureCube :( [Note that I am doing this only once]
RenderCommand::DrawIndexed(tempPipeline, 36);
}
提前致谢!
解决方案
创建渲染视图时,您没有指定要写入的切片。切片的正确描述是:
D3D11_RENDER_TARGET_VIEW_DESC renderTargetViewDesc = {};
renderTargetViewDesc.Format = textureDesc.Format;
renderTargetViewDesc.ViewDimension = D3D11_RTV_DIMENSION_TEXTURE2DARRAY;
renderTargetViewDesc.Texture2DArray.MipSlice = 0;
renderTargetViewDesc.Texture2DArray.FirstArraySlice =i;
renderTargetViewDesc.Texture2DArray.ArraySize = 1;
(注意:如果使用 MSAA,ViewDimension 将变为 D3D11_RTV_DIMENSION_TEXTURE2DMSARRAY)
还要为您的资源创建着色器视图,因为您想创建一个默认视图,您可以传递 NULL 而不是自制的 D3D11_SHADER_RESOURCE_VIEW_DESC
DX_CALL(DX11Internal::GetDevice()->CreateShaderResourceView(tex, NULL, &mSRV));
您还可以创建另一个渲染视图,一次性映射整个立方体贴图:
DX11Internal::GetDevice()->CreateRenderTargetView(tex, NULL, &cubeMapFullView);
但在这种情况下,您将需要使用几何着色器跨切片复制几何体(使用 SV_RenderTargetArrayIndex),或使用提供相同类型功能的供应商特定扩展。
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