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sqlite - 奇怪的 org.sqlite.SQLiteException: [SQLITE_ERROR] SQL 错误或缺少数据库（外键不匹配 -

问题描述

我正在运行into org.sqlite.SQLiteException: [SQLITE_ERROR] SQL error or missing database (foreign key mismatch - ...一个声明，使用普通的 SQLite 前端没有任何抱怨。这将创建我的数据库的关键部分：

CREATE TABLE IF NOT EXISTS artists (
    aid INTEGER PRIMARY KEY AUTOINCREMENT,
    aname VARCHAR(200) NOT NULL,
    CONSTRAINT one UNIQUE(aname)
);

CREATE TABLE IF NOT EXISTS discs (
    did INTEGER PRIMARY KEY AUTOINCREMENT,
    testAddCD1 BIGINT(10) NOT NULL,
    dtitle VARCHAR(125) NOT NULL,
    dreleaseyear YEAR(4) DEFAULT NULL,
    dlang VARCHAR(3) DEFAULT NULL
);

CREATE TABLE IF NOT EXISTS tracks (
    discs_did INTEGER NOT NULL,
    tnumber INT(4) NOT NULL,
    ttitle VARCHAR(125) NOT NULL,
    tseconds INT(4) NOT NULL,
    CONSTRAINT pk PRIMARY KEY(discs_did, tnumber),
    CONSTRAINT fk FOREIGN KEY(discs_did) REFERENCES discs(did) ON DELETE RESTRICT ON UPDATE RESTRICT,
    CONSTRAINT val CHECK(tseconds> 0)
);

CREATE TABLE IF NOT EXISTS track_by_artist (
    discs_did INTEGER NOT NULL,
    tracks_tnumber INT(4) NOT NULL,
    artists_aid INTEGER NOT NULL,
    CONSTRAINT pk PRIMARY KEY(discs_did, tracks_tnumber, artists_aid),
    CONSTRAINT fk1 FOREIGN KEY(discs_did) REFERENCES discs(did) ON DELETE RESTRICT ON UPDATE RESTRICT,
    CONSTRAINT fk2 FOREIGN KEY(tracks_tnumber) REFERENCES tracks(tnumber) ON DELETE RESTRICT ON UPDATE RESTRICT,
    CONSTRAINT fk3 FOREIGN KEY(artists_aid) REFERENCES artists(aid) ON DELETE RESTRICT ON UPDATE RESTRICT

数据库被创建，JDBC 驱动程序插入艺术家、光盘和光盘的曲目——一切都很好。最后的插入应该将一个艺术家分配给一个轨道，看起来像

INSERT INTO track_by_artist (discs_did, tracks_tnumber, artists_aid) VALUES (1, 1, 1);

使用 JDBC 这会产生

SQLite-Error #1
org.sqlite.SQLiteException: [SQLITE_ERROR] SQL error or missing database (foreign key mismatch - "track_by_artist" referencing "tracks")
    at org.sqlite.core.DB.newSQLException(DB.java:1012)
    at org.sqlite.core.DB.newSQLException(DB.java:1024)
    at org.sqlite.core.DB.throwex(DB.java:989)
    at org.sqlite.core.NativeDB.prepare_utf8(Native Method)
    at org.sqlite.core.NativeDB.prepare(NativeDB.java:134)
    at org.sqlite.core.DB.prepare(DB.java:257)
    at org.sqlite.core.CorePreparedStatement.<init>(CorePreparedStatement.java:45)
    at org.sqlite.jdbc3.JDBC3PreparedStatement.<init>(JDBC3PreparedStatement.java:30)
    at org.sqlite.jdbc4.JDBC4PreparedStatement.<init>(JDBC4PreparedStatement.java:25)
    at org.sqlite.jdbc4.JDBC4Connection.prepareStatement(JDBC4Connection.java:35)
    at org.sqlite.jdbc3.JDBC3Connection.prepareStatement(JDBC3Connection.java:241)
    at org.sqlite.jdbc3.JDBC3Connection.prepareStatement(JDBC3Connection.java:205)

使用 SQLite 的文本前端发出相同的 SQL-Insert 就像奶油一样。

我有点迷茫，不知道如何处理我的 Java 代码。

一些建议，请？

克里斯

标签： sqlitejdbckey

解决方案

问题是track_by_artist你定义了这个外键约束：

CONSTRAINT fk2 FOREIGN KEY(tracks_tnumber) REFERENCES tracks(tnumber) ON DELETE RESTRICT ON UPDATE RESTRICT

尽管tnumberintracks不是UNIQUE（也不应该是）。
外键的父项必须定义为UNIQUE。

intracks被PRIMARY KEY定义为 and 的组合discs_did，tnumber这是有道理的，所以这 2 列的组合是唯一的。

您可以做的是在track_by_artist复合外键中为列discs_did和tracks_tnumber该引用discs_did和tnumberof定义tracks：

CREATE TABLE IF NOT EXISTS track_by_artist (
    discs_did INTEGER NOT NULL,
    tracks_tnumber INT(4) NOT NULL,
    artists_aid INTEGER NOT NULL,
    CONSTRAINT pk PRIMARY KEY(discs_did, tracks_tnumber, artists_aid),
    CONSTRAINT fk1 FOREIGN KEY(discs_did, tracks_tnumber) REFERENCES tracks(discs_did, tnumber) ON DELETE RESTRICT ON UPDATE RESTRICT,
    CONSTRAINT fk2 FOREIGN KEY(artists_aid) REFERENCES artists(aid) ON DELETE RESTRICT ON UPDATE RESTRICT
);

这样您就不需要为discs_did.

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