c# - 返回时我收到错误`.. ASP.NET
问题描述
var result = JsonConvert.DeserializeObject<Risks>(jsonData);
var finalResult = result.Value.Where(x => x.ID == 5).ToList();
return finalResult;
我正在开发一个返回<IEnumerable<RiskValue>
反序列化不会导致任何错误的 API,当我返回最终结果时会显示此错误,知道是什么原因造成的吗?
System.InvalidOperationException: The JSON property name for 'HRDF_1.Models.RisksValue.ID' collides
with another property.
System.InvalidOperationException: The JSON property name for 'test_1.Models.RisksValue.ID' collides with another property.
at System.Text.Json.ThrowHelper.ThrowInvalidOperationException_SerializerPropertyNameConflict(Type type, JsonPropertyInfo jsonPropertyInfo)
解决方案
尝试在您的 Startup.cs中设置PropertyNameCaseInsensitive
为:false
services.AddControllers().AddJsonOptions(options => {
options.JsonSerializerOptions.PropertyNamingPolicy = null;
//the importance here..
options.JsonSerializerOptions.PropertyNameCaseInsensitive = false;
});