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python - 我如何让这个功能从卡组中选择？

问题描述

import random


deck = ['one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight', 'nine', 'ten', 'jack', 'queen', 'king', 'ace', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight', 'nine', 'ten', 'jack', 'queen', 'king', 'ace', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight', 'nine', 'ten', 'jack', 'queen', 'king', 'ace', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight', 'nine', 'ten', 'jack', 'queen', 'king', 'ace']

def dealer_total():
  dealer_total = 0
  while dealer_total < 16:
    dealer_card = random.choice(deck)
    deck.remove(dealer_card)
    if dealer_card == "one":
      dealer_total = dealer_total + 1
    if dealer_card == "two":
      dealer_total = dealer_total + 2
    if dealer_card == "three":
      dealer_total = dealer_total + 3
    if dealer_card == "four":
      dealer_total = dealer_total + 4
    if dealer_card == "five":
      dealer_total = dealer_total + 5
    if dealer_card == "six":
      dealer_total = dealer_total + 6
    if dealer_card == "seven":
      dealer_total = dealer_total + 7
    if dealer_card == "eight":
      dealer_total = dealer_total + 8
    if dealer_card == "nine":
      dealer_total = dealer_total + 9
    if dealer_card == "ten" or dealer_card == "jack" or dealer_card == "queen" or dealer_card == "king":
      dealer_total = dealer_total + 10
    if dealer_card == "ace":
      dealer_total = dealer_total + 11
  if dealer_total > 15:
    print(dealer_total)
  


def user_total(): 
  user_total = 0
  user_hit = input("Do you want to hit or stay? ")
  while user_hit.lower() == "hit":
    user_card = random.choice(deck)
    deck.remove(user_card)
    if user_card == "one":
      user_total = user_total + 1
    if user_card == "two":
      user_total = user_total + 2
    if user_card == "three":
      user_total = user_total + 3
    if user_card == "four":
      user_total = user_total + 4
    if user_card == "five":
      user_total = user_total + 5
    if user_card == "six":
      user_total = user_total + 6
    if user_card == "seven":
      user_total = user_total + 7
    if user_card == "eight":
      user_total = user_total + 8
    if user_card == "nine":
      user_total = user_total + 9
    if user_card == "ten" or user_card == "jack" or user_card == "queen" or user_card == "king":
      user_total = user_total + 10
    if user_card == "ace":
      user_total = user_total + 11
  print("Your total is", str(user_total) + ".")
  if user_total == 21:
    print("You win!")
  if user_total < 22 and user_hit == "stay":
    print(user_total)
  if user_total > 21:
    print("You busted!")

dealer_total()
user_total()

这是我的代码。每次我运行它时，它都会说“不能从空序列中选择”关于定义 user_card 的部分，即使它从列表中随机选择用于定义经销商卡。我也知道有一种更简洁的方法来做所有的 if 语句，我只是不知道如何去做，因为我是一个初学者编码器。任何帮助，将不胜感激。

标签： python

解决方案

这里的具体问题是您在循环之前while要求用户输入，但随后不要在while循环内要求新输入，以便条件可以更改以退出。

  user_hit = input("Do you want to hit or stay? ")
  while user_hit.lower() == "hit":

可能是（限制代码更改量）

  while input("Do you want to hit or stay? ").lower() == "hit":

接下来是循环的其余部分，从那时起，每个循环周期都会请求输入。

我还建议您使用字典来捕获卡片值（为什么同时存在“一”和“王牌”？），例如

card_value = {'one':1, 'two':2, 'three':3 # ... and so on

这将使您以后有机会使用以下表达式：

  dealer_total += card_value[dealer_card]

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