首页 > 解决方案 > 有没有办法在 Python 的 Pandas 数据框中通过 SMTPLib 将电子邮件连接到多个收件人?

问题描述

我有下面的代码来发送特定于熊猫数据框中某些地址的电子邮件。类型为 pandas.series。我怎样才能发送具有多个地址的每个列表?有些有多达 8 个电子邮件地址,用分号 (;) 分隔。发送出去的唯一可能性是发送到一个地址。从下面的数据框中,我可以将特定于 ID 的电子邮件发送到 TestEmail 值。没有任何东西适用于电子邮件。我收到以下错误:

SMTPRecipientsRefused: {'': (421, b'4.7.0 Too many protocol errors (6) on this connection, closing transmission channel.')}

数据框df

IDs  CompanyNames     Emails                                        TestEmail
2003    XXX           xx@gmail.com;yy@ryt.com;dd@xx.com;ii@dd.com    kk@kk.com
2004    XXXYY         xx@gmail.com;yy@ryt.com;dd@xx.com              kk@kk.com
2005    XXTTNN        xx@gmail.com;yy@ryt.com;dd@xx.com;ii@dd.com    kk@kk.com
2006    BBOOLL        xx@gmail.com;yy@ryt.com                        kk@kk.com

代码如下。对于单个地址,我可以将名称与 df['IDs'] 值匹配的附件发送到相应的电子邮件地址。

import smtplib, ssl
from email.message import EmailMessage
import getpass

ids = df['IDs']
emails_to = df['Emails'] #Pandas column with email addresses split  by semi-colon(;)
namesofcompanies  = df["CompanyNames"]
sendfrom  = df["SenderList"]

date_7days = (datetime.now() + timedelta(days=7)).strftime('%d/%m/%Y')
date_14days = (datetime.now() + timedelta(days=13)).strftime('%d/%m/%Y')

email_pass = input() #Office 365 password 
context=ssl.create_default_context()
for i in range(len(emails_to)): # iterate through the records
    # for every record get the name and the email addresses
    ID = str(ids[i])
    Emaitstosendto = emails_to[i]
    companynames = namesofcompanies[i]
    tosendfrom = sendfrom[i]
    
    if my_files_dict.get(ID): #Looks for  attachments in the same folder with same name  as the corresponding record 
        smtp_ssl_host = 'smtp.office365.com'
        smtp_ssl_port = 587
        email_login = "xxx@xxx.com" #Office 365 email  
        email_from = tosendfrom         
        email_to = Emaitstosendto
        
        msg = MIMEMultipart()
        msg['Subject'] = "Received Emails between "+date_7days+" - "+date_14days
        msg['From'] = email_from
        msg['To'] = email_to
        msg['X-Priority'] = '2'    
         
        text = ("XXXX,\n"                
                f"xxxxxx\n\n")
        
        msg.attach(MIMEText(text))
        filename = my_files_dict.get(ID)#Files in the folder matching the ID   
        fo = open(filename,'rb')

        s2 = smtplib.SMTP(smtp_ssl_host, smtp_ssl_port)
        s2.starttls(context=context)
        s2.login(email_login, email_pass) 
        attachment = email.mime.application.MIMEApplication(fo.read(),_subtype="xlsx")
        fo.close()
        attachment.add_header('Content-Disposition','attachment',filename=filename)

        msg.attach(attachment)        
        s2.send_message(msg)        
        s2.quit()  

标签: pythonpandasdataframeemailsmtplib

解决方案


取自这个答案:如何使用 python smtplib 向多个收件人发送电子邮件?

这是您必须更改的行:

首先将 email_to 拆分为不同电子邮件的列表,然后使用“,”加入

msg['To'] = ", ".join(email_to.split(";"))

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