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python - 检查键盘输入不起作用。请帮忙

问题描述

我正在尝试在此处提供并接受此代码：https ://stackoverflow.com/a/55369170/14307622 但我收到此错误。任何想法为什么？我是新来的，所以如果我违反了这个问题的一些规则，那么请告诉我，但如果可能的话，请先提出一些解决问题的方法。

import keyboard
import time

listedSongs = []
currentSong = "idk"
exit = False  # make a loop control variable

def alt_k():
    i = 1
    paused = False

def alt_q(): 
    global exit
    exit = True

def alt_s():
    if currentSong not in listedSongs:
        listedSongs.append(currentSong)
        print(listedSongs)

# assign hooks to the keyboard
keyboard.on_press_key("alt+k", alt_k)  # on press alt+k, execute alt_k()
keyboard.on_press_key("alt+q", alt_q)
keyboard.on_press_key("alt+s", alt_s)

# main loop
while not exit:
    keyboard.wait()  # "block" for input (essentially, do nothing until a key is pressed and yield CPU resources to anything else that wants them)

我得到的错误是：

Traceback (most recent call last):
  File "D:\AJ\Coding\test.py", line 26, in <module>
    keyboard.on_press_key("alt+k", alt_k)  # on press alt+k, execute alt_k()
  File "C:\Users\AJ\AppData\Local\Programs\Python\Python39\lib\site-packages\keyboard\__init__.py", line 510, in on_press_key
    return hook_key(key, lambda e: e.event_type == KEY_UP or callback(e), suppress=suppress)
  File "C:\Users\AJ\AppData\Local\Programs\Python\Python39\lib\site-packages\keyboard\__init__.py", line 493, in hook_key
    scan_codes = key_to_scan_codes(key)
  File "C:\Users\AJ\AppData\Local\Programs\Python\Python39\lib\site-packages\keyboard\__init__.py", line 324, in key_to_scan_codes
    raise ValueError('Key {} is not mapped to any known key.'.format(repr(key)), e)
ValueError: ("Key 'alt+k' is not mapped to any known key.", ValueError("Key name 'alt+k' is not mapped to any known key."))

标签： pythonkeyboard

解决方案

它似乎on_press_key()只适用于单键，q但不适用于组合alt+q。或者，这可能只是某些系统上的问题。至少它在我的 Linux 上不起作用。

或者他们可能会更改模块中的代码。检查键盘输入中的答案使用过多的 cpu 使用率，我的代码有问题吗？2岁。

你可以使用add_hotkey()它不需要wait()

import keyboard
import time

listedSongs = []
currentSong = "idk"

exit = False  # make a loop control variable

def alt_k():
    print('pressed: alt+k')
    
    i = 1
    paused = False

def alt_q(): 
    global exit  # need it to assign `True` to global/external variable instead of creating local variable

    print('pressed: alt+q')
    
    exit = True

def alt_s():
    print('pressed: alt+s')

    if currentSong not in listedSongs:
        listedSongs.append(currentSong)
        print(listedSongs)

keyboard.add_hotkey('alt+k', alt_k)
keyboard.add_hotkey('alt+q', alt_q)
keyboard.add_hotkey('alt+s', alt_s)

# main loop
while not exit:
    time.sleep(1)

请参阅文档中的示例：示例

最终您可以使用hotkye = read_hotkey(...)withif/else来执行正确的功能。

我不确定，但有时它也适用于我，hotkey = keyboard.wait(suppress=False)但有时它不起作用。

while not exit:
    hotkey = keyboard.read_hotkey(suppress=False)
    #hotkey = keyboard.wait(suppress=False)

    print('hotkey:', hotkey)

    if hotkey == 'alt+k':
        alt_k()
    elif hotkey == 'alt+q':
        alt_q()

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