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python - 如何将空格键绑定到 Tkinter 上的 2 个函数？

问题描述

所以我正在尝试制作一个计时器（如 cstimer.net），但我遇到了这个问题

我已经绑定了空格键来启动计时器，然后，一旦你启动了计时器，再次点击它就会停止它。问题是当我按下空格键时，它会启动并完成计时器。而且时间不会重置，它只会将经过的时间添加到最后一次。

这是我所做的：

import pyglet
import os
import time
from tkinter import *

# Import scripts
import sys
sys.path.insert(1, './scripts')

import scrambler
import timer
import saver

class Application():
    def __init__(self, app):
        self.app = app

        pyglet.font.add_file('./data/fonts/DS-DIGIB.TTF')  # Add the time font
        # Add the body (used for scramble and more elements) font
        pyglet.font.add_file('./data/fonts/OverPassMono-Light.ttf')

        # Create side panel
        self.sidepanel = Frame(self.app, bg='red', width=200, height=800)

        # Generate scramble
        self.scramble_output = scrambler.gen_333scramble()

        #Bind spacebar to start timer
        self.app.bind('<Key>', self.updater_start)

        # Define button, start time and scramble Widget and show them
        self.display = Label(self.app, text='0.00', bg='#232931', fg='white', anchor=CENTER, font=('DS-DIGITAL', 64), pady=100)
        self.scramble = Label(self.app, text=self.scramble_output, bg='#232931', fg='white', font=('Overpass Mono Light', 12), anchor=NW)
        self.start_button = Button(self.app, text='Start', fg='white', bg='#4ecca3', command=self.start, anchor=CENTER)
            
        #Show in grid
        self.display.grid(row=1, column=1, sticky=EW, padx=275, pady=150)
        self.start_button.grid(row=2, column=1, columnspan=2, padx=275, sticky=N, ipadx=20)
        self.scramble.grid(row=0, column=1, sticky=EW, padx=275)


    def start(self):
        # Unshow last time or starting time
        self.display.grid_remove()

        # Start counting time
        self.start_time = timer.start()

        #Bind spacebar to stop timer

        self.app.bind('<Key>', self.updater_stop)

         # Create widgets to show the timer is running and finish button
        self.state = Label(self.app, text='.', bg='#232931', fg='white', font=('DS-DIGITAL', 32))
        self.state.grid(row=1, column=1, sticky=EW, padx=560, pady=300)
        self.finish_button = Button(self.app, text='FINISH', fg='white', bg='#4ecca3', command=self.finish)
        self.finish_button.grid(row=2, column=1, columnspan=2, padx=275, sticky=N, ipadx=20)

        # Unshow start button and scramble widgets

        self.start_button.grid_remove()
        self.scramble.grid_remove()

    def updater_start(self, e):  
        if e.keysym=='space':
            print('Hitted spacebar')
            self.start()

    def updater_stop(self, e):
        if e.keysym=='space':
            print('Hitted spacebar')
            self.finish()

    def finish(self):
        self.message = timer.finish(self.start_time)
        # Display formatted time
        self.display = Label(self.app, text=self.message, bg='#232931', fg='white', font=('DS-DIGITAL', 64), pady=100)


        #Save time on times.json
        saver.save_time(self.message, self.scramble_output)

        # Unshow state and finish button widgets
        self.finish_button.grid_remove()
        self.state.grid_remove()

        # Redefine widgets
        self.start_button = Button(self.app, text='Start', fg='white', bg='#4ecca3', command=self.start)
        self.scramble_output = scrambler.gen_333scramble()
        self.scramble = Label(self.app, text=self.scramble_output, bg='#232931', fg='white', font=('Overpass Mono Light', 12), anchor=NW)

        # Show widgets on screen and formatted time
        self.display.grid(row=1, column=1, sticky=EW, padx=275, pady=150)
        self.start_button.grid(row=2, column=1, columnspan=2, padx=275, sticky=N, ipadx=20)
        self.scramble.grid(row=0, column=1, sticky=EW, padx=275)

只是为了让您知道，saver、timer和scrambler模块是我制作的脚本，因此我可以对代码进行切片。计时器脚本只是在开始时获取 time.time() 变量并将其与当前时间相减，然后将其格式化为小时：秒：分钟。

标签： pythontkinter

解决方案

我建议为按空格键的次数设置一个变量。绑定空格键时，检查是否为偶数（0、2、4等）。这意味着它应该启动。否则，它应该结束。

from tkinter import *

root = Tk()
NUM_SPACE_PRESS = 0


def space_press(e):
    global NUM_SPACE_PRESS
    if NUM_SPACE_PRESS % 2 == 0:
        Label(text='<start here>').pack()
        NUM_SPACE_PRESS += 1
    else:
        Label(text='<end here>').pack()
        NUM_SPACE_PRESS += 1


root.bind("<space>", space_press)

root.mainloop()

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