javascript - pg client.query() 不等待 await

Question

我不明白为什么客户端请求await前面pg的代码在函数内部代码之前运行之后似乎不能作为代码工作client.query()。

const {Pool, Client} = require('pg')
const connectionString = 'postgressql://user@localhost:5432/database'

const client = new Client({
    connectionString:connectionString
})

client.connect()

database_func()

async function database_func() {
  await client.query(`SELECT t FROM es ORDER BY t DESC LIMIT 1;`, (err,res) => {
    console.log('res')
    return;
  })
  client.end()
  console.log('after res')
}

我希望上面能返回这个：

=> res
=> after res

相反，它返回：

=> after res
=> res

标签： javascriptpostgresqlasync-awaitpg

Answer 1

尝试

const {Pool, Client} = require('pg')
const connectionString = 'postgressql://user@localhost:5432/database'

const client = new Client({
    connectionString:connectionString
})

client.connect()

database_func();

function database_func() {
  client.query(`SELECT t FROM es ORDER BY t DESC LIMIT 1;`, (err,res) => {
    console.log('res')
    client.end()
    console.log('after res')
    return;
  })
}

使用承诺：

const {Pool, Client} = require('pg')
const connectionString = 'postgressql://user@localhost:5432/database'

database_func().then(() => console.log('done'))

function async database_func() {
  const client = new Client({
    connectionString:connectionString
  });
  client.connect()
  await query_func(client, `SELECT t FROM es ORDER BY t DESC LIMIT 1;`);
  await query_func(client, `SELECT t FROM es ORDER BY t LIMIT 1;`);
  client.end()
}

function query_func(client, query) {
  return new Promise((resolve, reject) => {
    client.query(query, (err,res) => {
      if(err) reject(err);
      resolve(res);       
    }
  });
}