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php - 检查数组中的所有值是否都存在于数据库列中

问题描述

我有一系列电子邮件，我想通过验证我的数据库来检查所有这些电子邮件是否有效。我想将无效的电子邮件（如果有）添加到一个空数组中。我对 MySQL 不太熟悉，所以我需要一些帮助。这是我目前在我的 PHP 文件中的内容：

<?php

$conn = mysqli_connect($servername, $username, $password, $db);
$conn->select_db($db);

if($conn->connect_error) {
    die("Connection failed " . $conn->connect_error);
}
echo "Connected successfully\n";

$tags = preg_split("/\,/", $_POST['tags']);
$invalidEmails = array();
$count = 0;

$result = $conn->query("SELECT mail FROM dej_colleagues");
for ($i = 0; $i < sizeof($tags); $i++) {
    $trim_brackets = trim($tags[$i], '[]');
    $trim_quotes = trim($trim_brackets, '"');
    
    while ($row = mysqli_fetch_array($result, MYSQL_ASSOC)) {
        if ($trim_quotes == $row["mail"]) {
            $count += 1;
        }
        else {
            array_push($invalidEmails, $tags[i]);
        }
    }
}
if (sizeof($tags) == $count) {
    echo "good";
}
?>

我的数据库连接成功，但即使我的标签数组中的电子邮件存在于数据库中，它也没有检测到它。此外，数据库列有 100k 个条目，所以如果您知道更有效的方法，请告诉我。

标签： phpmysqldatabasemysqli

解决方案

建立一个语句WHERE IN来获取匹配的邮件，然后比较结果数组会更有效。您可以使用array_diff()来获取数组的差异。

<?php

mysqli_report(MYSQLI_REPORT_ERROR | MYSQLI_REPORT_STRICT);
$conn = mysqli_connect($servername, $username, $password, $db);

echo "Connected successfully\n";

$tags = preg_split("/\,/", $_POST['tags']);
$invalidEmails = array();
$count = 0;

// modify your array how you want it
foreach ($tags as $i => $tag) {
    $trim_brackets = trim($tag, '[]');
    $trim_quotes = trim($trim_brackets, '"');
    $tags[$i] = $trim_quotes;
}

// build placeholders for WHERE IN
$in = str_repeat('?,', count($tags) - 1) . '?';
// prepare query
$stmt = $conn->prepare("SELECT mail FROM dej_colleagues WHERE mail IN ($in)");
// bind an array of values. First params is a type list.
$stmt->bind_param(str_repeat('s', count($tags)), ...$tags);
$stmt->execute();
$results = $stmt->get_result();
// fetch the matching mails into an array
$mails = [];
foreach ($results as $row) {
    $mails[] = $row['mail'];
}

// get the difference between the two arrays
$invalidEmails = array_diff($tags, $mails);

if (count($tags) === count($mails)) {
    echo "good";
}

var_dump($invalidEmails);

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