c# - 您如何在运行时比较具有不同属性的对象？

问题描述

我的代码结构是这样的

class Drawing()
{
ObjectType = "Drawing";
}

class Shape() : Drawing()
{
DrawingType = "Shape";
}

class square() : Shape()
{
ShapeType = "square";
}

class circle() : Shape()
{
ShapeType = "circle";
}

class triangle() : Shape()
{
ShapeType = "triangle";
}

class lines() : Drawing()
{
DrawingType = "lines";
}

class horizontal() : lines()
{
linesType = "horizontal";
}

class vertical() : lines()
{
linesType = "vertical";
}

etc...

我试图找出解决这个问题的正确逻辑，所以这张图片是我所拥有的简单表示。

我有一个类似于图片中的对象结构，它们都继承了它们上面的级别。它们都具有其类型的属性。它们都会有 ObjectType，第 2 层有 DrawingType，第 3 层有 ShapeType、LineType 或 PointType……

例如，正方形会有

square {
ObjectType = "drawing";
DrawingType = "shapes";
ShapeType = "square"
}

但是，垂直将具有不同的属性

vertical {
    ObjectType = "drawing";
    DrawingType = "lines";
    LineType = "vertical"
    }

现在我的问题是，假设我希望用户根据他们的输入选择一些东西，我该怎么做？就像假设用户输入“正方形”一样，我将如何选择正方形？如果属性相同，那将很容易，因为我可以比较它们。但是我该如何使用这样的结构呢？

标签： c#algorithmlogic

解决方案

由于这些所有类都派生自一个基类，因此所有子类都包含来自父类的属性。对象级别比较将引导您将一个绘图对象与另一个对象进行比较，因为所有对象都仅从那里派生。因此，我实施了 IComparer 以获得您想要的结果->

这是代码->>

主要课程：

Drawing drawing1 = new Drawing();
        Drawing drawing2 = new Drawing();
        drawing2.ObjectType = "newdrawing";

        Shape shape = new Shape();
        triangle triangle1 = new triangle();
        triangle triangle2 = new triangle();
        triangle2.ShapeType = "another";

        //all -1 is not equals and 0 is equals
        int result1 = drawing1.Compare(drawing1, drawing2);
        int result2 = drawing1.Compare(drawing1, drawing1);

        int result3 = drawing1.Compare(drawing1, shape);
        int result4 = shape.Compare(shape, triangle1);

        int result5 = triangle1.Compare(triangle1, triangle2);

其他类：

public class Drawing : IComparer
{
    public string ObjectType { get; set; } = "Drawing";

    public int Compare(object x, object y)
    {
        //returning 0 is equals
        if (x.GetType().Name == y.GetType().Name)
        {
            switch (x.GetType().Name)
            {
                case "Drawing":
                    return ((Drawing)x).ObjectType == ((Drawing)y).ObjectType ? 0 : -1;
                case "Shape":
                    return ((Shape)x).DrawingType == ((Shape)y).DrawingType ? 0 : -1;
                case "square":
                    return ((square)x).ShapeType == ((square)y).ShapeType ? 0 : -1;
                case "triangle":
                    return ((triangle)x).ShapeType == ((triangle)y).ShapeType ? 0 : -1;
                default:
                    return -1; // Not equal
            }
        }
        return -1; // Not equal
    }
}

class Shape : Drawing
{
    public string DrawingType { get; set; } = "Shape";

}

class square : Shape
{
    public string ShapeType { get; set; } = "square";
}

class circle : Shape
{
    public string ShapeType { get; set; } = "circle";
}

class triangle : Shape
{
    public string ShapeType { get; set; } = "triangle";
}

class lines : Drawing
{
    public string DrawingType { get; set; } = "lines";
}

class horizontal : lines
{
    public string linesType { get; set; } = "horizontal";
}

class vertical : lines
{
    public string linesType { get; set; } = "vertical";
}

希望这对你有用。请写回您的代码片段，具体不起作用。干杯

c# - 您如何在运行时比较具有不同属性的对象？

问题描述

解决方案

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