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awk - sed，匹配2个模式（包括）之间的所有行，然后将第二个匹配放在顶部

问题描述

这是我需要做的：

输入：（Python）

## This is a function,
## its purpose is... yada yada yada
def function_name(x):
    return x + 1

输出：（降价）

## function_name
This is a function,
its purpose is... yada yada yada

到目前为止，我得到了：

sed -n '/## /,/def/ { /## \|def/ p }' TEST.py | cut -d' ' -f2- | sed 's/(.*)\(.*\)://'

产生：

This is a function,
its purpose is... yada yada yada
function_name

有2个条件：

1.- “##”和“def”之间不匹配任何这些模式的行应该被忽略。

例子：

输入：（Python）

## This is a function,
## its purpose is... yada yada yada
# This is a normal comment, nothing to see here! (ignored)
def function_name(x):
    return x + 1

输出：（降价）

## function_name
This is a function,
its purpose is... yada yada yada

2.- 第二种模式必须被概括，例如，而不是使用“def”，假设我想使用“类”。

输入：（Python）

## This is a class,
## its purpose is... yada yada yada
# This is a normal comment, nothing to see here! (ignored)
class class_name:
    __init__(self, x):
        self.x = x

输出：（降价）

## class_name
This is a class,
its purpose is... yada yada yada

标签： awksed

解决方案

在每个 Unix 机器上的任何 shell 中使用任何 awk（如果你的 awk 不支持 POSIX 字符类，则使用它）a-zA-Z0-9：[:alnum:]

$ cat tst.awk
sub(/^## */,"") {
    cmts = cmts $0 ORS
    next
}

sub(/^[[:alnum:]_]+ */,"") {
    sub(/[^[:alnum:]_].*/,"")
    print "##", $0
    print cmts
    cmts = ""
}


$ awk -f tst.awk file
## function_name
This is a function,
its purpose is... yada yada yada

## function_name
This is a function,
its purpose is... yada yada yada

## class_name
This is a class,
its purpose is... yada yada yada

以上是在这个输入文件上运行的：

$ cat file
## This is a function,
## its purpose is... yada yada yada
def function_name(x):
    return x + 1

## This is a function,
## its purpose is... yada yada yada
# This is a normal comment, nothing to see here! (ignored)
def function_name(x):
    return x + 1

## This is a class,
## its purpose is... yada yada yada
# This is a normal comment, nothing to see here! (ignored)
class class_name:
    __init__(self, x):
        self.x = x

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