javascript - MySql 表的 Ajax 搜索以从结果中创建 href 链接
问题描述
我目前有一个可以工作并返回结果的 Ajax 搜索功能。但是,我无法让搜索结果成为 href 链接,因此它将搜索找到的“payroll_number”添加到 url 中,例如成为 Candidatecard.php?pr=1388。其中 1388 是工资单号
<a href="candidatecard.php?pr='.$Result['payroll_number'].'">
我的网页代码:
<h2>Payroll <span>Number Search</span></h2>
<!-- Search box. -->
<input type="text" id="search" placeholder="Payroll Number Search" />
<b>Eg: </b><i>5100, 6237, 7259. </i>
<!-- Suggestions will be displayed in below div. -->
<?php
echo "<a href='candidatecard.php?pr=$pn'>Search $pn</a>";
?>
<div id="display"></div>
我的js代码
//Getting value from "ajax.php".
function fill(Value) {
//Assigning value to "search" div in "search.php" file.
$('#search').val(Value);
//Hiding "display" div in "search.php" file.
$('#display').hide();
}
$(document).ready(function() {
//On pressing a key on "Search box" in "search.php" file. This function will be called.
$("#search").keyup(function() {
//Assigning search box value to javascript variable payroll_numberd as "payroll_number".
var payroll_number = $('#search').val();
//Validating, if "payroll_number" is empty.
if (payroll_number == "") {
//Assigning empty value to "display" div in "search.php" file.
$("#display").html("");
}
//If payroll_number is not empty.
else {
//AJAX is called.
$.ajax({
//AJAX type is "Post".
type: "POST",
//Data will be sent to "ajax.php".
url: "ajax.php",
//Data, that will be sent to "ajax.php".
data: {
//Assigning value of "payroll_number" into "search" variable.
search: payroll_number
},
//If result found, this funtion will be called.
success: function(html) {
//Assigning result to "display" div in "search.php" file.
$("#display").html(html).show();
}
});
}
});
});
我的阿贾克斯代码:
<?php
//Including Database configuration file.
include "Include/db.php";
//Getting value of "search" variable from "script.js".
if (isset($_POST['search'])) {
//Search box value assigning to $payroll_number variable.
$payroll_number = $_POST['search'];
//Search query.
$Query = "SELECT payroll_number FROM candidatedetails WHERE payroll_number LIKE
'%$payroll_number%' LIMIT 10";
//Query execution
$ExecQuery = MySQLi_query($con, $Query);
//Creating unordered list to display result.
echo '
<ul>
';
//Fetching result from database.
while ($Result = MySQLi_fetch_array($ExecQuery)) {
?>
<!-- Creating unordered list items.
Calling javascript function named as "fill" found in "script.js" file.
By passing fetched result as parameter. -->
<li onclick='fill("<?php echo $Result['payroll_number']; ?>")'>
<a>
<!-- Assigning searched result in "Search box" in "search.php" file. -->
<?php echo $Result['payroll_number'];?>
</li></a>
<!-- Assign searchbox result to pn variable.-->
<?php$pn = $Result['payroll_number'];?>
<!-- Closing parenthesis. -->
<?php
}}
?>
</ul>
解决方案
推荐阅读
- python-3.x - json.decoder.JSONDecodeError:期望值:第 1 行第 1 列(字符 0)和 204 响应
- python - 使用列表理解简化 for 循环和 if 语句
- vb.net - 反序列化 Json 以获得多语言支持
- reactjs - Bootstrap 4 flex容器调整到视口大小以创建不换行或溢出到下一行?
- python-3.x - 在推特上打开链接
- r - 在 R 中拆分数据框列
- swift - 可以在结构(而不是类)中使用组合吗?
- python - 在遍历它时从熊猫数据框中删除行
- r - 返回数据框列表中的唯一行
- c# - 将日期 json 解析为 DateTime