时间戳

首页 > 解决方案 > 从数组中获取单个数据插入到php中的数组中

php - 从数组中获取单个数据插入到php中的数组中

问题描述

我想从这个数组中获取数据。我需要 id,tvtitle,tvmedia,tvlanguage,tvlogo,tvgroup 值才能插入 mysql 。

这是我的数组：

        Array
       (
        [0] => Array
            (
                [id] => 1
                [tvtitle] => 1.Anando TV
                [tvmedia] => https://tempx.jagobd.com:441/c5V6mmMyX7RpbEU9Mi8xNy8yMDEOGIDU6RgzQ6NTAgdEoaeFzbF92YWxIZTO0U0ezN1IzMyfvcGVMZEJCTEFWeVN3PT0mdFsaWRtaW51aiPhnPTI/anandatv.stream/chunks.m3u8
                [tvlanguage] => Bangla
                [tvlogo] => https://i.imgur.com/WpMA9kC.png
                [tvgroup] => Bangladeshi
            )
    
        [1] => Array
            (
                [id] => 2
                [tvtitle] => 2.Asian TV
                [tvmedia] => http://209.126.120.153/hls/asiantv.m3u8
                [tvlanguage] => Bangla
                [tvlogo] => https://s4.gifyu.com/images/imageca9d0bcf608394fd.png
                [tvgroup] => Bangladeshi
            )
    
        [2] => Array
            (
                [id] => 3
                [tvtitle] => 3.ATN Bangla
                [tvmedia] => https://tempx.jagobd.com:441/c5V6mmMyX7RpbEU9Mi8xNy8yMDEOGIDU6RgzQ6NTAgdEoaeFzbF92YWxIZTO0U0ezN1IzMyfvcGVMZEJCTEFWeVN3PT0mdFsaWRtaW51aiPhnPTI/atnbd-8-org.stream/chunks.m3u8
                [tvlanguage] => Bangla
                [tvlogo] => https://s6.gifyu.com/images/image27cfa7002786c232.png
                [tvgroup] => Bangladeshi
            )
    
        [3] => Array
            (
                [id] => 4
                [tvtitle] => 4.ATN News
                [tvmedia] => https://tempx.jagobd.com:441/c5V6mmMyX7RpbEU9Mi8xNy8yMDEOGIDU6RgzQ6NTAgdEoaeFzbF92YWxIZTO0U0ezN1IzMyfvcGVMZEJCTEFWeVN3PT0mdFsaWRtaW51aiPhnPTI/atnws-sg.stream/chunks.m3u8
                [tvlanguage] => Bangla
                [tvlogo] => https://s4.gifyu.com/images/image2b075f0e0fd37461.png
                [tvgroup] => Bangladeshi
            )
)

我试过了，但我只能得到值而不是单个数据。帮助我。

foreach($items as $row => $innerArray){
           foreach($innerArray as $innerRow => $value){
             echo $value["id"];
             echo "<br/>";
           }
         }

提前致谢

标签： phpmysqlarrays

解决方案

<?php

$array_1 = array();

$d1 = array("id"=>"1", "tvtitle"=>"A", "tvmedia"=>"A", "tvlanguage"=>"A", "tvlogo"=>"A", "tvgroup"=>"A");
$d2 = array("id"=>"2", "tvtitle"=>"A", "tvmedia"=>"A", "tvlanguage"=>"A", "tvlogo"=>"A", "tvgroup"=>"A");
$d3 = array("id"=>"3", "tvtitle"=>"A", "tvmedia"=>"A", "tvlanguage"=>"A", "tvlogo"=>"A", "tvgroup"=>"A");
$d4 = array("id"=>"4", "tvtitle"=>"A", "tvmedia"=>"A", "tvlanguage"=>"A", "tvlogo"=>"A", "tvgroup"=>"A");
$d5 = array("id"=>"5", "tvtitle"=>"A", "tvmedia"=>"A", "tvlanguage"=>"A", "tvlogo"=>"A", "tvgroup"=>"A");

$array_1[0] = $d1;
$array_1[1] = $d2;
$array_1[2] = $d3;
$array_1[3] = $d4;
$array_1[4] = $d5;

for ($i=0; $i<count($array_1); $i++)
{
    echo $array_1[$i]["id"];
    echo "<br/>";
}

?>

推荐阅读