首页 > 解决方案 > 如何在 Swift 5 中解析来自 Alamofire 的模型结构的 JSON 响应?

问题描述

我尝试使用 Alamofire 发布 mysql 数据库,但我成功了,但我的响应似乎不是 json,我想将响应值传递给模型结构。我试过这段代码。哪里错了?如果您能提供帮助,我将不胜感激。

 func register(registerModel:RegisterResponse,completion:@escaping (RegisterModel?)->() ){
    let parameters: [String: Any] =
    [
        "email": "\(registerModel.email)",
        "password": "\(registerModel.password)",
        "first_name": "\(registerModel.first_name)",
        "last_name": "\(registerModel.last_name)",
    ]
   
    AF.request(registerUrl,method: .post,parameters: parameters,encoding: URLEncoding.httpBody,headers: nil).responseJSON(){ response in
       //debugPrint(response)
        switch response.result{
        
        case .success(let data):
        
                if response.data != nil {
                    
                    print(data)
                    completion(data as? RegisterModel)
                    
                }
            
          
        case .failure(let err):
            print(err.localizedDescription)
        }
    }
    
}

输出:

{
result = "account already exists";
tf = 0;
verificationCode = "<null>";
}

标签: swiftalamofireswift5

解决方案


假设您RegisterResponseDecodable,只需使用responseDecodable

AF.request(registerUrl, method: .post, parameters: parameters, encoding: URLEncoding.httpBody)
  .responseDecodable(of: RegisterResponse.self) { response in
    // Handle response.
  }

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