python - 如何停止/恢复循环而不必终止终端？

Question

这是一个游戏的小宏。

我想用 F9 键停止程序（不要关闭它！），然后当我再次单击 F9 时，它将恢复。如果可能，无需退出游戏。

F9 - 启动/停止程序

import pyautogui
import time
import keyboard

print("Press F10 to stop and F9 to start")

while keyboard.is_pressed('f10') == False:

    if keyboard.is_pressed('f9') == True:
        time.sleep(3)
        pyautogui.press('w')
        time.sleep(1)
        pyautogui.press('s')
        time.sleep(1)
        pyautogui.press('w')
        time.sleep(1)
        pyautogui.press('s')
        time.sleep(1)
    
    pyautogui.press('a')
    time.sleep(4)
    pyautogui.press('t')

标签： pythonpython-3.x

Answer 1

你可以使用pynput来监控键盘

from time import sleep
from threading import Thread

from pynput.keyboard import Key, Listener, Controller

def on_press(key):
    if key == Key.f9: # start and stop the macro
        flags['running'] = not flags['running']
    elif key == Key.f10: # closes the program
        flags['exit'] = True
        return False # stop the listener

def macro(flags):
    keyboard = Controller()
    while not flags['exit']:
        if flags['running']: # your macro here
            sleep(3)
            keyboard.type('w')
            # etc...
            

flags = {'running' : True, 'exit' : False}

macro_thread = Thread(target=macro, args=(flags,))
macro_thread.start()

# Collect events until released
with Listener(on_press=on_press) as listener:
    listener.join()
    
macro_thread.join()

如果您希望代码立即停止，您需要更改宏函数内的睡眠：

from time import time

def check_exit(s, flags):
    """ checks if the exit flag becomes true for s seconds """
    start = time()
    while time() < (start + s):
        if flags['exit']:
            return True
    return False

def macro(flags):
    keyboard = Controller()
    while not flags['exit']:
        if flags['running']:
            if check_exit(3, flags): return
            keyboard.type('w')
            # etc...