python - Plotly 下拉菜单执行功能

Question

我正在尝试使用 plotly 下拉菜单来执行绘图功能。

我编写了一个函数，它将根据输入值（“状态”）生成多个子图。似乎在下拉列表中选择一个将执行我的功能的状态应该是相对微不足道的，但是我已经用尽了很多资源。

下拉值应该是 list(option_dict.keys())，任何帮助将不胜感激！

功能代码如下：

def plot_generator(state, option_dict):    
deltas = new_delta_dict(option_dict)    # generate a fresh delta dict for the respective region

state_dict = deltas[state].copy()
state_dict = collections.OrderedDict(sorted(state_dict.items()))
state_dfs = total_dfs(state_dict)     # get the count of total dataframes in dict (nested)

state_plots = {}
for dates in list(state_dict):
    for option_type in state_dict[dates]:
        plotname = str(dates[0]) + ' ' + str(dates[1]) + ' ' + option_type
        sub_df = state_dict[dates][option_type]
        ## Rename the tuples in the columns ##
        newcols = list(sub_df)[:-2]
        newcols = ['{}_{}'.format(x[0],x[1]) for x in newcols]
        keepcols = list(sub_df)[-2:]
        colnames = newcols + keepcols
        sub_df.columns = colnames
        # Generate the plot
        state_plots[plotname] = px.line(sub_df)
        
# Generate the figures
fig = make_subplots(rows = len(state_plots), cols=1, subplot_titles=list(state_plots))

for i, plotname in enumerate(list(state_plots)):
    for dat in state_plots[plotname].data:
        fig.add_trace((go.Scatter(x=dat['x'], y=dat['y'], name=dat['name'])), row=i+1, col=1)
        # Obtain vline from underlying_dict
        vline_date = (int(plotname[:4]), str(plotname[5:7]))
        if 'American' in plotname:
            vline_type = 'American'
        elif 'European' in plotname:
            vline_type = 'European'
        else: print('Option Type Error')
        # Obtain underlying and add to figure
        fig.add_vline(x=underlying_dict[state][vline_date][vline_type], line_width=2, line_dash="dash", row=i+1, col=1)
        
fig.layout.template=None

fig.update_layout(height=(state_dfs*100), width=800, title=("{} Option Payoff Diagrams".format(state)))
return fig

标签： pythonplotly