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python - 在python的目录中解压.bz2文件

问题描述

我想解压缩一个文件夹中包含的一堆 .bz2 文件（其中还有 .zst 文件）。我正在做的是以下内容：

 destination_folder = "/destination_folder_path/"

 compressed_files_path="/compressedfiles_folder_path/"

 dirListing = os.listdir(compressed_files_path)

 for file in dirListing:

     if ".bz2" in file:

        unpackedfile = bz2.BZ2File(file)
        data = unpackedfile.read()
        open(destination_folder, 'wb').write(data)

但我不断收到以下错误消息：

Traceback (most recent call last):
  File "mycode.py", line 34, in <module>
    unpackedfile = bz2.BZ2File(file)
  File ".../miniconda3/lib/python3.9/bz2.py", line 85, in __init__
    self._fp = _builtin_open(filename, mode)
FileNotFoundError: [Errno 2] No such file or directory: 'filename.bz2'

为什么我会收到此错误？

标签： pythoncompression

解决方案

您必须确保您使用的所有文件路径都存在。最好使用正在打开的文件的完整路径。


import os
import bz2


# this path must exist
destination_folder = "/full_path_to/folder/"

compressed_files_path = "/full_path_to_other/folder/"

# get list with filenames (strings)
dirListing = os.listdir(compressed_files_path)

for file in dirListing:
    # ^ this is only filename.ext
    if ".bz2" in file:
        
        # concatenation of directory path and filename.bz2
        existing_file_path = os.path.join(compressed_files_path, file)

        # read the file as you want
        unpackedfile = bz2.BZ2File(existing_file_path)
        data = unpackedfile.read()

        new_file_path = os.path.join(destination_folder, file)
        with bz2.open(new_file_path, 'wb') as f:
            f.write(data)

您还可以使用 shutil 模块来复制或移动文件。

os.path.exists

os.path.join

舒蒂尔

bz2 示例

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